Splitting

ruby-talk
1

Hi,

I suppose that:
".".split(".")
will give me array with two empty strings instead of empty array.

How can I do that?

Thanks,
Dawid

2

#Ok, instead of
irb(main):065:0> "...text...".split(".")
=> ["", "", "", "text"]

#I should do something like this:
irb(main):066:0> "...text...".split(".",-1)
=> ["", "", "", "text", "", "", ""]

Strange...

3

There is nothing before or after the period.

irb(main):001:0> " . ".split('.')
=> [" ", " "]
irb(main):002:0> ".".split('.')
=>

···

On Mar 4, 1:00 pm, DMG <dawid.mar...@gmail.com> wrote:

Hi,

I suppose that:
".".split(".")
will give me array with two empty strings instead of empty array.

How can I do that?

--
Luis Lavena

4

$ ri String#split
str.split(pattern=$;, [limit])
  If the limit parameter is omitted, trailing null fields are
     suppressed. If limit is a positive number, at most that number of
     fields will be returned (if limit is 1, the entire string is
     returned as the only entry in an array). If negative, there is no
     limit to the number of fields returned, and trailing null fields
     are not suppressed.

···

On 4 March 2010 14:35, Luis Lavena <luislavena@gmail.com> wrote:

On Mar 4, 1:00 pm, DMG <dawid.mar...@gmail.com> wrote:
> Hi,
>
> I suppose that:
> ".".split(".")
> will give me array with two empty strings instead of empty array.
>
> How can I do that?

There is nothing before or after the period.

irb(main):001:0> " . ".split('.')
=> [" ", " "]
irb(main):002:0> ".".split('.')
=>

--
Luis Lavena