(I ordered for a copy of Mastering Regular Expressions. Should be in my
snail mailbox anytime soon. In the meantime ... )
How do I tell Ruby to use the content of a variable as the pattern,
rather than interpreting the variable name as a literal?
v = "aeiou"
Then, in
"goodness" =~ /[v]/
I'd like v to be interepreted not as a literal but as a variable name.
Thanks
basi
String interpolation seems to work on regular expressions so try:
"goodness" =~ /[#{v}]/
Or more verbosely:
"goodness" =~ Regexp.new("[#{v}]")
enjoy,
.adam
basi wrote:
(I ordered for a copy of Mastering Regular Expressions. Should be in my
snail mailbox anytime soon. In the meantime ... )How do I tell Ruby to use the content of a variable as the pattern,
rather than interpreting the variable name as a literal?v = "aeiou"
Then, in
"goodness" =~ /[v]/
I'd like v to be interepreted not as a literal but as a variable name.
Same as with a string:
"goodness" =~ /[#{v}]/
--
vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407
basi wrote:
(I ordered for a copy of Mastering Regular Expressions. Should be in my
snail mailbox anytime soon. In the meantime ... )How do I tell Ruby to use the content of a variable as the pattern,
rather than interpreting the variable name as a literal?v = "aeiou"
Then, in
"goodness" =~ /[v]/
I'd like v to be interepreted not as a literal but as a variable name.
Thanks
basi
"goodness" =~ /#{v}/
thanks to all who replied. so simple. (goodness, why didn't I think of
that. sigh.)
basi
Timothy Hunter wrote:
basi wrote:
> (I ordered for a copy of Mastering Regular Expressions. Should be in my
> snail mailbox anytime soon. In the meantime ... )
>
> How do I tell Ruby to use the content of a variable as the pattern,
> rather than interpreting the variable name as a literal?
>
>
> v = "aeiou"
>
> Then, in
>
> "goodness" =~ /[v]/
>
> I'd like v to be interepreted not as a literal but as a variable name.
>
> Thanks
> basi
>"goodness" =~ /#{v}/