I have the following variable. Ruby looks at the = sign as a regex
literal and I need it to be recognized as text.
search_text =! %r{
ruby-1.8.7-p302 > pattern = %r{=}
=>
ruby-1.8.7-p302 > pattern.inspect
=> "/=/"
ruby-1.8.7-p302 > "abc=xyz" =~ pattern
=> 3
Maybe I'm not understanding your issue?
···
On Wed, Feb 2, 2011 at 10:19 AM, Bob Hatch <roberth@monavie.com> wrote:
I have the following variable. Ruby looks at the = sign as a regex
literal and I need it to be recognized as text.search_text =! %r{
}x
--
Hassan Schroeder ------------------------ hassan.schroeder@gmail.com
twitter: @hassan
You have a typo in your code sample here, and the message you see as a
result is:
warning: regex literal in condition
That is because of the =! you have. Ruby breaks that down into an
assigment (the = part) and a boolean negation (the ! part) of the
following regexp. You need to change the =! to just = as follows:
search_text = %r{
···
On 2/2/2011 12:19 PM, Bob Hatch wrote:
I have the following variable. Ruby looks at the = sign as a regex
literal and I need it to be recognized as text.search_text =! %r{
=
}x
=
}
-Jeremy
I think he meant to use =~ instead.
···
On Wed, Feb 2, 2011 at 1:37 PM, Jeremy Bopp <jeremy@bopp.net> wrote:
On 2/2/2011 12:19 PM, Bob Hatch wrote:
I have the following variable. Ruby looks at the = sign as a regex
literal and I need it to be recognized as text.search_text =! %r{
}x
You have a typo in your code sample here, and the message you see as a
result is:warning: regex literal in condition
That is because of the =! you have. Ruby breaks that down into an
assigment (the = part) and a boolean negation (the ! part) of the
following regexp. You need to change the =! to just = as follows:search_text = %r{
}
That's a possibility, but take a look at the conversations in recent
threads opened by Bob. You'll find that he's using this search_text
variable to hold a regexp in an ongoing series of problems he's running
into while writing a script to basically perform an fgrep operation on a
file. I actually suggested he try out this particular method for
specifying his regexp and assigning it to search_text, so I assumed he
ran into this problem while implementing that. 
-Jeremy
···
On 02/02/2011 09:50 PM, Eric Christopherson wrote:
On Wed, Feb 2, 2011 at 1:37 PM, Jeremy Bopp <jeremy@bopp.net> wrote:
On 2/2/2011 12:19 PM, Bob Hatch wrote:
I have the following variable. Ruby looks at the = sign as a regex
literal and I need it to be recognized as text.search_text =! %r{
=
}xYou have a typo in your code sample here, and the message you see as a
result is:warning: regex literal in condition
That is because of the =! you have. Ruby breaks that down into an
assigment (the = part) and a boolean negation (the ! part) of the
following regexp. You need to change the =! to just = as follows:search_text = %r{
}
I think he meant to use =~ instead.