Why is this returning nil?

ruby-talk
1

class User

    def initialize(level, status)
        @level = level
        @status = status
    end

    def finda
        if @status == "active"
            print #{@level}
        else
        puts "user not exist"
        end
    end
end

user1 = User.new(1, "active")
user2 = User.new(1, "inactive")
user3 = User.new(2, "active")
user4 = User.new(3, "inactive")

user1.finda

Something wrong ..not sure
TIA
Stuart

2

        if @status == "active"
            print #{@level}
     
               print @level

outside a string, # is a comment :slight_smile:

        else

Guy Decoux

3

print and puts return nil. As they are the last commands executed
their return statuses are returned.

Farrel

···

On 09/08/06, Dark Ambient <sambient@gmail.com> wrote:

class User

    def initialize(level, status)
        @level = level
        @status = status
    end

    def finda
        if @status == "active"
            print #{@level}
        else
        puts "user not exist"
        end
    end
end

user1 = User.new(1, "active")
user2 = User.new(1, "inactive")
user3 = User.new(2, "active")
user4 = User.new(3, "inactive")

user1.finda

Something wrong ..not sure
TIA
Stuart

4

2 things..
1. Change "print #{@level}" to "print @level"
2. print and puts both return nil

Mark

5

Because methods return the value of the last statement. In this case, both 'puts' and 'print' return nil, the actual output to the screen is separate from the return value:

print "Hello\n"
Hello
=> nil
puts "Hello"
Hello
=> nil

My guess/advice would be to return the actual string you're eventually going to output, and deal with the actual output elsewhere in the code.

matthew smillie.

···

On Aug 9, 2006, at 17:23, Dark Ambient wrote:

class User

   def initialize(level, status)
       @level = level
       @status = status
   end

   def finda
       if @status == "active"
           print #{@level}
       else
       puts "user not exist"
       end
   end
end

user1 = User.new(1, "active")
user2 = User.new(1, "inactive")
user3 = User.new(2, "active")
user4 = User.new(3, "inactive")

user1.finda

Something wrong ..not sure
TIA
Stuart

6

Hello!

You forgot quotes in line print #{@level}. Change it to "print
#{@level}" please.

···

2006/8/9, Dark Ambient <sambient@gmail.com>:

class User

    def initialize(level, status)
        @level = level
        @status = status
    end

    def finda
        if @status == "active"
            print #{@level}
        else
        puts "user not exist"
        end
    end
end

user1 = User.new(1, "active")
user2 = User.new(1, "inactive")
user3 = User.new(2, "active")
user4 = User.new(3, "inactive")

user1.finda

Something wrong ..not sure
TIA
Stuart

--
Alexey Vakhov mailto:vakhov@gmail.com

7

Oh. Some mistake. Change it to

print " #{@level}"

of course :slight_smile:

···

2006/8/9, Alexey Vakhov <vakhov@gmail.com>:

Hello!

You forgot quotes in line print #{@level}. Change it to "print
#{@level}" please.

2006/8/9, Dark Ambient <sambient@gmail.com>:
> class User
>
> def initialize(level, status)
> @level = level
> @status = status
> end
>
> def finda
> if @status == "active"
> print #{@level}
> else
> puts "user not exist"
> end
> end
> end
>
> user1 = User.new(1, "active")
> user2 = User.new(1, "inactive")
> user3 = User.new(2, "active")
> user4 = User.new(3, "inactive")
>
> user1.finda
>
> Something wrong ..not sure
> TIA
> Stuart
>

--
Alexey Vakhov mailto:vakhov@gmail.com

--
Alexey Vakhov mailto:vakhov@gmail.com

8

Wow..lot of answers, thanks to all.
It works and I've learned a few things in the process.

Stuart

···

On 8/9/06, Alexey Vakhov <vakhov@gmail.com> wrote:

Hello!

You forgot quotes in line print #{@level}. Change it to "print
#{@level}" please.

2006/8/9, Dark Ambient <sambient@gmail.com>:
> class User
>
> def initialize(level, status)
> @level = level
> @status = status
> end
>
> def finda
> if @status == "active"
> print #{@level}
> else
> puts "user not exist"
> end
> end
> end
>
> user1 = User.new(1, "active")
> user2 = User.new(1, "inactive")
> user3 = User.new(2, "active")
> user4 = User.new(3, "inactive")
>
> user1.finda
>
> Something wrong ..not sure
> TIA
> Stuart
>

--
Alexey Vakhov mailto:vakhov@gmail.com