What's the best way to split this kind of string?

ruby-talk
1

Hi!

I'm trying to make a routine to make a Morris Number Sequence.
(http://www.ocf.berkeley.edu/~stoll/number_sequence.html)
I need to split a string in the following way, for example.

"111223133" => ["111", "22", "3", "1", "33"]

I can loop thru the string by each character, comparing with the
previous character.
But is there a quick and easy way?
Probably a regular expression?

Thanks.

Sam

2

Sam Kong wrote:

Hi!

I'm trying to make a routine to make a Morris Number Sequence.
(http://www.ocf.berkeley.edu/~stoll/number_sequence.html\)
I need to split a string in the following way, for example.

"111223133" => ["111", "22", "3", "1", "33"]

I can loop thru the string by each character, comparing with the
previous character.
But is there a quick and easy way?
Probably a regular expression?

This seems to work:

"111223133".scan(/1+|2+|3+|4+|5+|6+|7+|8+|9+|0+/)
=> ["111", "22", "3", "1", "33"]

···

--
-- Jim Weirich

--
Posted via http://www.ruby-forum.com/\.

3

Maybe something like:

  s.scan(/(\d)(\1*)/).map! { |e| e.join }
  # => ["111", "22", "3", "1", "33"]

or:

  s.scan(/0+|1+|2+|3+|4+|5+|6+|7+|8+|9+/)
  # => ["111", "22", "3", "1", "33"]

···

On Mon, 2006-03-13 at 16:58 +0900, Sam Kong wrote:

Hi!

I'm trying to make a routine to make a Morris Number Sequence.
(http://www.ocf.berkeley.edu/~stoll/number_sequence.html\)
I need to split a string in the following way, for example.

"111223133" => ["111", "22", "3", "1", "33"]

I can loop thru the string by each character, comparing with the
previous character.
But is there a quick and easy way?
Probably a regular expression?

--
Ross Bamford - rosco@roscopeco.REMOVE.co.uk

4

Sam Kong wrote:

Hi!

I'm trying to make a routine to make a Morris Number Sequence.
(http://www.ocf.berkeley.edu/~stoll/number_sequence.html\)
I need to split a string in the following way, for example.

"111223133" => ["111", "22", "3", "1", "33"]

I can loop thru the string by each character, comparing with the
previous character.
But is there a quick and easy way?
Probably a regular expression?

Thanks.

Sam

"111223133".scan(/(.)(\1*)/).map{|x|x.join}

5

Hmm.... Clever

···

On 3/13/06, Ross Bamford <rossrt@roscopeco.co.uk> wrote:

Maybe something like:

        s.scan(/(\d)(\1*)/).map! { |e| e.join }
        # => ["111", "22", "3", "1", "33"]

--
Thiago Arrais

6

[snip]

Maybe something like:

  s.scan(/(\d)(\1*)/).map! { |e| e.join }
  # => ["111", "22", "3", "1", "33"]

or:

  s.scan(/0+|1+|2+|3+|4+|5+|6+|7+|8+|9+/)
  # => ["111", "22", "3", "1", "33"]

Or:

  s.scan(/((.)\2*)/).transpose[0]

Boy, are my fingers glad to save those keystrokes :slight_smile:

andrew

···

On Mon, 13 Mar 2006 17:23:56 +0900, Ross Bamford <rossrt@roscopeco.co.uk> wrote:

--
Andrew L. Johnson http://www.siaris.net/
      They're not soaking, they're rusting!
          -- my wife (on my dishwashing habits)