Hi,
str = "ABCD12A2012"
I need to divide the string into "ABCD" and "12A2012" i.e. right at the
start of a number in the string
i can use str.partition(%r(\d)) which gives me ["ABCD","1","2A2012"]. I
can club the last two sub strings to get the work done. But is there a
better way to do so?
--
Posted via http://www.ruby-forum.com/.
Hi,
You can use String#split with a lookahead regex and a limit of 2:
str = "ABCD12A2012"
p str.split /(?=\d)/, 2
--
Posted via http://www.ruby-forum.com/.
Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str).captures
=> ["ABCD", "12A2012"]
Or more generic:
match_data = Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str)
match_data[0] # The whole matched string:
=> "ABCD12A2012"
match_data[1] # The content within first ( ):
=> "ABCD"
match_data[2] # The content within second ( ):
=> "12A2012"
Or if you are using Ruby 1.9 (time to move on):
match_data = Regexp.new(/^(?<first_portion>[a-zA-Z]+)(?<second_portion>.+)$/).match(str)
match_data["first_portion"]
=> "ABCD"
match_data["second_portion"]
=> "12A2012"
2012/6/7 cyber c. <lists@ruby-forum.com>:
str = "ABCD12A2012"
I need to divide the string into "ABCD" and "12A2012" i.e. right at the
start of a number in the stringi can use str.partition(%r(\d)) which gives me ["ABCD","1","2A2012"]. I
can club the last two sub strings to get the work done. But is there a
better way to do so?
--
Iñaki Baz Castillo
<ibc@aliax.net>
I need to divide the string into "ABCD" and "12A2012" i.e. right at the
start of a number in the string
Does this work?
str = "ABCD12A2012"
p str.split(/(\d.*\z)/) #> ["ABCD", "12A2012"]
Harry
I just saw on ruby forum that you already had a solution that you liked.
Your reply did not show up on ruby talk (not in my inbox, anyway.)
Sorry for the noise.
Harry
On Fri, Jun 8, 2012 at 1:09 PM, Harry Kakueki <list.push@gmail.com> wrote:
I need to divide the string into "ABCD" and "12A2012" i.e. right at the
start of a number in the string
"Iñaki Baz Castillo" <ibc@aliax.net> wrote in post #1063634:
2012/6/7 cyber c. <lists@ruby-forum.com>:
Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str).captures
Why are you using Regexp.new, when /^([a-zA-Z]+)(.+)$/ already *is* a
Regexp? This seems nonsensical to me, like String.new("abc").
--
Posted via http://www.ruby-forum.com/\.
Yes, I'm used to store my regexps in some module/class constants and
usually use Regexp.new for some reason I don't remember right now,
maybe because it allows passing a string which is useful in certain
cases:
Regexp.new("^([a-zA-Z]+)(.+)$")
But right, in my previous code I was passing a Regexp instance to
Regexp.new, which is not cool, sure 
2012/6/8 Jan E. <lists@ruby-forum.com>:
"Iñaki Baz Castillo" <ibc@aliax.net> wrote in post #1063634:
2012/6/7 cyber c. <lists@ruby-forum.com>:
Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str).capturesWhy are you using Regexp.new, when /^([a-zA-Z]+)(.+)$/ already *is* a
Regexp? This seems nonsensical to me, like String.new("abc").
--
Iñaki Baz Castillo
<ibc@aliax.net>
Like
irb(main):001:0> s = "foo"
=> "foo"
irb(main):002:0> rx = /^([a-zA-Z]+)#{s}(.+)$/
=> /^([a-zA-Z]+)foo(.+)$/
irb(main):003:0> puts rx
(?-mix:^([a-zA-Z]+)foo(.+)$)
=> nil
?
Kind regards
robert
On Fri, Jun 8, 2012 at 12:20 PM, Iñaki Baz Castillo <ibc@aliax.net> wrote:
2012/6/8 Jan E. <lists@ruby-forum.com>:
"Iñaki Baz Castillo" <ibc@aliax.net> wrote in post #1063634:
2012/6/7 cyber c. <lists@ruby-forum.com>:
Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str).capturesWhy are you using Regexp.new, when /^([a-zA-Z]+)(.+)$/ already *is* a
Regexp? This seems nonsensical to me, like String.new("abc").Yes, I'm used to store my regexps in some module/class constants and
usually use Regexp.new for some reason I don't remember right now,
maybe because it allows passing a string which is useful in certain
cases:Regexp.new("^([a-zA-Z]+)(.+)$")
--
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/