Is there a function that acts like String.left? I’d like to be able to
get the leftmost x characters of the string. e.g.:
“1234567890”.left(4) => "1234"
“x”.left(4) => “x”
String#slice and it’s synonym String#
~$ ruby -e ‘p “1234567890”[0,4]’ # from pos 0, 4 chars
“1234”
~$ ruby -e ‘p “1234567890”[0…3]’ # chars of given range
“1234”
~$ ruby -e ‘p “1234567890”[/^.{4}/]’ # with a regexp
“1234”
Pick your favorite 
– Nikodemus
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On Mon, 10 Jun 2002, Philip Mak wrote:
Is there a function that acts like String.left? I’d like to be able to
get the leftmost x characters of the string. e.g.:
“1234567890”.slice(0,4)
or
“1234567890”[0…4]
or
“1234567890”[0,4]
or
see http://www.rubycentral.com/book/ref_c_string.html
“Philip Mak” pmak@animeglobe.com wrote in message
news:20020609234140.GI9947@trapezoid.interserver.net…
···
Is there a function that acts like String.left? I’d like to be able to
get the leftmost x characters of the string. e.g.:“1234567890”.left(4) => “1234”
“x”.left(4) => “x”
Nikodemus Siivola wrote:
Is there a function that acts like String.left? I’d like to be able to
get the leftmost x characters of the string. e.g.:String#slice and it’s synonym String#
~$ ruby -e ‘p “1234567890”[0,4]’ # from pos 0, 4 chars
“1234”
~$ ruby -e ‘p “1234567890”[0…3]’ # chars of given range
“1234”
~$ ruby -e ‘p “1234567890”[/^.{4}/]’ # with a regexp
“1234”Pick your favorite
…and decide how you want to handle strings shorter than 4 
p “123”[0,4] # ==> “123”
p “123”[0…3] # ==> “123”
p “123”[/^.{4}/] # ==> nil
p “123”[/^.{0,4}/] # ==> “123”
···
On Mon, 10 Jun 2002, Philip Mak wrote: