What is the correct way to trim off the the first 37 characters of a
string?
I want to trim off the value from position 0 -> pos 37 or take off all
characters from right side and stopping at a specific character #.
myval = wererwerwerwerweritop123233434345556#personID
How is this done? Thanks.
MC
···
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Posted via http://www.ruby-forum.com/.
What is the correct way to trim off the the first 37 characters of a
string?
I want to trim off the value from position 0 -> pos 37 or take off all
characters from right side and stopping at a specific character #.
myval = wererwerwerwerweritop123233434345556#personID
How is this done? Thanks.
MC
--
Several ways:
myval = 'wererwerwerwerweritop123233434345556#personID'
=> "wererwerwerwerweritop123233434345556#personID"
myval[37..-1]
=> "personID"
myval.split('#',2).last
=> "personID"
myval[/[^#]*\z/]
=> "personID"
Take your pick!
-Rob
Rob Biedenharn http://agileconsultingllc.com
Rob@AgileConsultingLLC.com
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On Jan 22, 2009, at 3:09 PM, Mmcolli00 Mom wrote: