Hi, I've been playing Ruby for a few months now.
Yesterday I came across an interesting problem.
If I have this string:
abcd1234abc123
Now I want to separate the digit group with the non-digit group into an
array like this ["abcd",1234,"abc",123]. It's like re.split in Python.
How can I do it in Ruby with the least lines of code possible?
'abcd1234abc123'.split(/\d+/) only returns ["abcd","abc"]
Thank you in advance
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Gary C40 wrote:
If I have this string:
abcd1234abc123
Now I want to separate the digit group with the non-digit group into an
array like this ["abcd",1234,"abc",123]. It's like re.split in Python.
How can I do it in Ruby with the least lines of code possible?
'abcd1234abc123'.split(/\d+/) only returns ["abcd","abc"]
If the regex has capturing groups you'll get those in the array as well.
'abcd1234abc123'.split(/(\d+)/) #=> ["abcd", "1234", "abc", "123"]
If you need the numbers as integers, you could use something like:
'abcd1234abc123'.scan(/(\D+)(\d+)?/).map {|nd,d| [nd,d.to_i]}
#=> [["abcd", 1234], ["abc", 123]]
(Maybe add flatten and compact)
or
res=
'abcd1234abc123'.scan(/(\D+)(\d+)?/) do
res << $1
res << $2.to_i if $2
end
res #=> ["abcd", 1234, "abc", 123]
HTH,
Sebastian
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ICQ: 205544826
And the highly esoteric version...
n = []
s = []
'abcd1234abc123'.each_byte { | x |
if (47..57).include?(x)
then s << ; n.last << x
else n << ; s.last << x
end
}
n = n.reject { | x | x.empty? }.map { | x |
x.map {| y | y.chr }.join("").to_i }
s = s.reject { | x | x.empty? }.map { | x |
x.map { | y | y.chr }.join("") }
result = if n.length > s.length
then n.zip(s).flatten.compact
else s.zip(n).flatten.compact
end
p result # => ["abcd", 1234, "abc", 123]
Regards,
Jordan
On Dec 15, 9:16 am, Gary C40 <gary...@garyc40.com> wrote:
Hi, I've been playing Ruby for a few months now.
Yesterday I came across an interesting problem.
If I have this string:
abcd1234abc123
Now I want to separate the digit group with the non-digit group into an
array like this ["abcd",1234,"abc",123]. It's like re.split in Python.
How can I do it in Ruby with the least lines of code possible?
'abcd1234abc123'.split(/\d+/) only returns ["abcd","abc"]
Thank you in advance
--
Posted viahttp://www.ruby-forum.com/.
Just another one:
'abcd1234abc123'.scan(/\D+|\d+/) # ["abcd", "1234", "abc", "123"]
-- fxn
On Dec 15, 2007, at 4:39 PM, Sebastian Hungerecker wrote:
Gary C40 wrote:
If I have this string:
abcd1234abc123
Now I want to separate the digit group with the non-digit group into an
array like this ["abcd",1234,"abc",123]. It's like re.split in Python.
How can I do it in Ruby with the least lines of code possible?
'abcd1234abc123'.split(/\d+/) only returns ["abcd","abc"]If the regex has capturing groups you'll get those in the array as well.
'abcd1234abc123'.split(/(\d+)/) #=> ["abcd", "1234", "abc", "123"]If you need the numbers as integers, you could use something like:
'abcd1234abc123'.scan(/(\D+)(\d+)?/).map {|nd,d| [nd,d.to_i]}
#=> [["abcd", 1234], ["abc", 123]]
(Maybe add flatten and compact)
And another, from 1.9:
irb(main):004:0> str.split /(?<=\D)(?=\d)|(?<=\d)(?=\D)/
=> ["abcd", "1234", "abc", "123"]
On Dec 15, 8:47 am, Xavier Noria <f...@hashref.com> wrote:
On Dec 15, 2007, at 4:39 PM, Sebastian Hungerecker wrote:
> Gary C40 wrote:
>> If I have this string:
>> abcd1234abc123
>> Now I want to separate the digit group with the non-digit group
>> into an
>> array like this ["abcd",1234,"abc",123]. It's like re.split in
>> Python.
>> How can I do it in Ruby with the least lines of code possible?
>> 'abcd1234abc123'.split(/\d+/) only returns ["abcd","abc"]> If the regex has capturing groups you'll get those in the array as
> well.
> 'abcd1234abc123'.split(/(\d+)/) #=> ["abcd", "1234", "abc", "123"]> If you need the numbers as integers, you could use something like:
> 'abcd1234abc123'.scan(/(\D+)(\d+)?/).map {|nd,d| [nd,d.to_i]}
> #=> [["abcd", 1234], ["abc", 123]]
> (Maybe add flatten and compact)Just another one:
'abcd1234abc123'.scan(/\D+|\d+/) # ["abcd", "1234", "abc", "123"]
Phrogz wrote:
On Dec 15, 8:47 am, Xavier Noria <f...@hashref.com> wrote:
And another, from 1.9:
Yet another, after "gem install facets" and require "facets/string":
'abcd1234abc123'.shatter(/\d+/)
Wow, there sure are more than one way to solve a problem in Ruby.
Thanks for your help, I'll try them out 
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