Hi guys.
I want to know the time remain before an expiration.
If I do t_remained = Time.now - expiration I get a float object.
how can I convert it back to Time(days hours and minute)?
thanks
···
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Hi guys.
I want to know the time remain before an expiration.
If I do t_remained = Time.now - expiration I get a float object.
how can I convert it back to Time(days hours and minute)?
thanks
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I have tried this:
t = Time.now
=> Thu Mar 13 12:57:47 +0100 2008
t1 = Time.now + 1.hours
=> Thu Mar 13 13:58:03 +0100 2008
t2 = t1 - t
=> 3615.968256
tot = Time.at(t2)
=> Thu Jan 01 02:00:15 +0100 1970
but I don't know why the difference between t1 e t is 2 hours and not 1
hour?
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Stefano Bortolotti wrote:
I have tried this:
t = Time.now
=> Thu Mar 13 12:57:47 +0100 2008
t1 = Time.now + 1.hours
=> Thu Mar 13 13:58:03 +0100 2008
t2 = t1 - t
=> 3615.968256
tot = Time.at(t2)
=> Thu Jan 01 02:00:15 +0100 1970
but I don't know why the difference between t1 e t is 2 hours and not 1 hour?
a Time object doesn't represent a duration (2 hours) it represents a point in time (Jan 1st 1970, 2am). There's no standard Ruby object representing a time duration, but it seems that a Float (number of seconds) is good enough.
you can always do (num_of_seconds / 1.hour) to give you a fractional number of hours etc.
Gareth
I have tried this:
t = Time.now
=> Thu Mar 13 12:57:47 +0100 2008
t1 = Time.now + 1.hours
=> Thu Mar 13 13:58:03 +0100 2008
t2 = t1 - t
=> 3615.968256
tot = Time.at(t2)
=> Thu Jan 01 02:00:15 +0100 1970
but I don't know why the difference between t1 e t is 2 hours and not 1
hour?
t = Time.now
=> Thu Mar 13 09:26:37 -0400 2008
t1 = Time.now + 3600
=> Thu Mar 13 10:26:56 -0400 2008
t2 = t1 - t
=> 3618.385132
Time.at(t2)
=> Wed Dec 31 20:00:18 -0500 1969
Because you're not looking at the time zone (+0100).
-Rob
Rob Biedenharn http://agileconsultingllc.com
Rob@AgileConsultingLLC.com
On Mar 13, 2008, at 8:02 AM, Stefano Bortolotti wrote:
Thanks guys! I have done this:
def remaining_time
if expiration != nil
diff = expiration - Time.now
days = (diff / 1.day).to_i
hours = ((diff / 1.hour) % 24).to_i
mins = ((diff / 1.minute) 60).to_i
if diff < 7.days
return days.to_s + "gg, " + hours.to_s + ":" + mins.to_s
else
return "more than 7 days"
end
end
end
I'll try to improve it! If you have some advices, they are wellcomes..
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Since you have 1.day, 1.hour, 1.min, I assume that you have ActiveSupport and likely have Rails. In any case, you can use distance_of_time_in_words
If you want to clean up your own method:
days, dayfrac = diff.divmod(1.day)
hours, hrfrac = dayfrac.divmod(1.hour)
mins, secs = hrfrac.divmod(1.min)
if days >= 7
return "more than 7 days"
else
result =
result << "%sgg,"%days unless days.zero?
result << "%d:%0d"%[hours,mins]
return result.join(' ')
end
-Rob
Rob Biedenharn http://agileconsultingllc.com
Rob@AgileConsultingLLC.com
On Mar 13, 2008, at 12:11 PM, Stefano Bortolotti wrote:
Thanks guys! I have done this:
def remaining_time
if expiration != nil
diff = expiration - Time.nowdays = (diff / 1.day).to_i
hours = ((diff / 1.hour) % 24).to_i
mins = ((diff / 1.minute) 60).to_iif diff < 7.days
return days.to_s + "gg, " + hours.to_s + ":" + mins.to_s
else
return "more than 7 days"
end
end
endI'll try to improve it! If you have some advices, they are wellcomes..
Rob Biedenharn wrote:
if days >= 7
return "more than 7 days"
else
result =
result << "%sgg,"%days unless days.zero?
result << "%d:%0d"%[hours,mins]
return result.join(' ')
end
Also, there is the duration gem :
http://wiki.rubyonrails.org/rails/pages/Duration .
Regards,
Siep
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Rob Biedenharn wrote:
If you want to clean up your own method:
days, dayfrac = diff.divmod(1.day)
hours, hrfrac = dayfrac.divmod(1.hour)
mins, secs = hrfrac.divmod(1.min)if days >= 7
return "more than 7 days"
else
result =
result << "%sgg,"%days unless days.zero?
result << "%d:%0d"%[hours,mins]
return result.join(' ')
end-Rob
Rob Biedenharn http://agileconsultingllc.com
Rob@AgileConsultingLLC.com
Thanks Rob, I knew about distance_of_time_in_words but I want my own
method.
Cool the divmod..
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