(mandriva,eclipse) extract digits from fixnums

ruby-talk
1

hi,

I want to do a basic thing but without succes:
if a=1232, let nb_nb=4 (the number of digits)
for i from 1 to nb_nb, I want the following results:
i=1 => res=1 (first digit of a) and NOT the number 01 (with a zero in front of the 1)
i=2 => res=2 (same thing)
i=3 => res=3
i=4 => res=2

I tried a few things, like convert the number in array (it seems to keep the "0" in the result)...

do you have a solution?

olivier.

···

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2

You could try

a.to_s.split(//).collect {|s| s.to_i}

and extract nb_nb elements.

Bob Schaaf

···

On Apr 30, 2009, at 7:54 AM, lolveley wrote:

hi,

I want to do a basic thing but without succes:
if a=1232, let nb_nb=4 (the number of digits)
for i from 1 to nb_nb, I want the following results:
i=1 => res=1 (first digit of a) and NOT the number 01 (with a zero in front of the 1)
i=2 => res=2 (same thing)
i=3 => res=3
i=4 => res=2

I tried a few things, like convert the number in array (it seems to keep the "0" in the result)...

do you have a solution?

olivier.

___________________________________________________________________________ Yahoo! Mail réinvente le mail ! Découvrez le nouveau Yahoo! Mail et son interface révolutionnaire.
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3

Olivier Lolveley wrote:

hi,

I want to do a basic thing but without succes:
if a=1232, let nb_nb=4 (the number of digits)
for i from 1 to nb_nb, I want the following results:
i=1 => res=1 (first digit of a) and NOT the number 01 (with a zero in
front of the 1)
i=2 => res=2 (same thing)
i=3 => res=3
i=4 => res=2

I tried a few things, like convert the number in array (it seems to keep
the "0" in the result)...

do you have a solution?

It's not clear to me what you want to do, but maybe this will help:

a=1232
str = a.to_s
p str

--output:--
"1232"

digits =
str.length.times do |i|
  digits << str[i, 1]
end

p digits

--output:--
["1", "2", "3", "2"]

res=1 (first digit of a) and NOT the number 01

1 and 01 are the same *number*.

···

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