Guy-
Thanks, but a follow-up question:
How exactly would I rewrite my file (which happens to be named “dl.rb”) which currently includes just this text:
require ‘ftools’
File.safe_unlink(“.\output*.*”)
Do you think this code should be correct as written? (I don’t understand your “ruby -rftools -e” text.)
NOTE: In case it makes a difference, I’m using ruby on an NT machine.
Thanks!
-Kurt
···
-----Original Message-----
From: ts [mailto:decoux@moulon.inra.fr]
Sent: Wednesday, August 14, 2002 12:59 AM
To: ruby-talk@ruby-lang.org
Cc: ruby-talk@ruby-lang.org
Subject: Re: How to use the safe_unlink method?
File.safe_unlink(“.\output*.*”)
Well, it work fine
pigeon% ls -d .*
./ …/ .output*.*
pigeon%
pigeon% ruby -rftools -e ‘File.safe_unlink(“.\output*.*”)’
pigeon%
pigeon% ls -d .*
./ …/
pigeon%
safe_unlink don’t accept meta-characters like *
Guy Decoux
He’s creating a file named “.output*.*” and deleting it with the line
you used. He’s showing you 2 errors there:
- usage of '' in the string: it’s gotta be escaped: “\”
NOTE: maybe Ruby uses ‘/’ as a dir. separator even in Win*, you’ll
have to test
- File.safe_unlink doesn’t accept file globs.
Use something like (untested)
require ‘ftools’
files = Dir[“.\output\.”]
files.each { |x| File.safe_unlink x }
···
On Thu, Aug 15, 2002 at 03:01:41AM +0900, Kurt Euler wrote:
Guy-
Thanks, but a follow-up question:
How exactly would I rewrite my file (which happens to be named “dl.rb”) which currently includes just this text:
require ‘ftools’
File.safe_unlink(“.\output*.*”)
Do you think this code should be correct as written? (I don’t
understand your “ruby -rftools -e” text.)
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