There must be a better way of converting dates than this ugly mess ?
def convert_date format, s
case format
when "yymmddhhmmss"
year = s[0,2].to_i + 2000
month= s[2,2].to_i
day = s[4,2].to_i
hour = s[6,2].to_i
minute=s[8,2].to_i
second=s[10,2].to_i
Time.local(year,month,day,hour,minute,second)
when "yyyymmddhhmm"
year = s[0,4].to_i
month= s[4,2].to_i
day = s[6,2].to_i
hour = s[8,2].to_i
minute=s[10,2].to_i
Time.local(year,month,day,hour,minute)
when "ddmmyyhhmm"
day = s[0,2].to_i
month= s[2,2].to_i
year = s[4,2].to_i + 2000
hour = s[6,2].to_i
minute=s[8,2].to_i
Time.local(year,month,day,hour,minute)
when "yyyymmdd"
year = s[0,4].to_i
month= s[4,2].to_i
day = s[6,2].to_i
Time.local(year,month,day)
end
end
Christer
···
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Posted via http://www.ruby-forum.com/.
Christer Nilsson wrote:
There must be a better way of converting dates than this ugly mess ?
def convert_date format, s
case format
when "yymmddhhmmss"
year = s[0,2].to_i + 2000
month= s[2,2].to_i
day = s[4,2].to_i
hour = s[6,2].to_i
minute=s[8,2].to_i
second=s[10,2].to_i
Time.local(year,month,day,hour,minute,second)
when "yyyymmddhhmm"
year = s[0,4].to_i
month= s[4,2].to_i
day = s[6,2].to_i
hour = s[8,2].to_i
minute=s[10,2].to_i
Time.local(year,month,day,hour,minute)
when "ddmmyyhhmm"
day = s[0,2].to_i
month= s[2,2].to_i
year = s[4,2].to_i + 2000
hour = s[6,2].to_i
minute=s[8,2].to_i
Time.local(year,month,day,hour,minute)
when "yyyymmdd"
year = s[0,4].to_i
month= s[4,2].to_i
day = s[6,2].to_i
Time.local(year,month,day)
end
Christer
I'm not too sure about the + 2000 part of the year calculation. It seems to be missing the pivot.
The real problem is that there are so many different date formats and none of them are *sensible*. You could write some fsm to parse the string of "ymdhms" symbols and give yourself a pat on the back for your coding skills or you could just use the code and get on with something more interesting. As a point of note there is the question of the year values, there should be an else clause to raise an error and there is no checking that the values are sensible (or even numbers), does format.size == s.size etc.
Yes to code looks ugly but I would be more concerned about the possible errors than it not being /nice/.
Sometimes ugly is the best you can get.
David A. Black wrote:
See Date.parse.
Thank you, David.
Your hint collapsed my code.
Christer
def convert_date format, s
raise "illegal date " + format + " " + s unless format.size == s.size
s = "20" + s if format[0,6]=="yymmdd"
s = "20" + s[4,2] + s[2,2] + s[0,2] + s[6,4] if
format[0,10]=="ddmmyyhhmm"
DateTime.parse(s)
end
···
--
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