Convert String "1;2;3;4;5;" to Array [1, 2, 3, 4, 5]

ruby-talk
1

I'm trying to convert a String of numbers that are separated by
semicolons to an Array---totally for fun, to stretch my ruby
understanding, fyi.

I use the Array in a while loop which does work when the Array looks
like = [1,2,3,4,5,...]---so that part is working. But I want to use ruby
to
convert a String = "1;2;3;4;5;6;7;8;9;10" into an Array [1,2,3,4,5,...]
so
that I can use these values.

I've tried many a method, but can't seem to get the desired result; I've
tried gsub(/\;/, ","), eval (), and others.

···

##########

raw_data = "1;2;3;4;5;6;7;8;9;10"
data = raw_data.split(/\;/) #but this gives ["1", "2", "3", "4", "5",
"6", "7", "8", "9", "10"], not [1, 2, 3,...]

#data = [1,2,3,4,5,6,7,8,9,10,11,12] # this is the desired result

boundary = 1
ending_boundary = 13
interval = (ending_boundary - boundary)/3

while boundary < ending_boundary
    print "For the class #{boundary} to #{boundary + interval}, "
    print "the group is: "
    puts data.select{ |x| x >= boundary && x < (boundary + interval)
}.size
    print data.select{ |x| x >= boundary && x < (boundary + interval)
}.join(' ')
    boundary = boundary + interval #increase the boundary to the next
class
    print ".\n"
end

--
Posted via http://www.ruby-forum.com/.

2

I'm trying to convert a String of numbers that are separated by
semicolons to an Array---totally for fun, to stretch my ruby
understanding, fyi.

I use the Array in a while loop which does work when the Array looks
like = [1,2,3,4,5,...]---so that part is working. But I want to use ruby
to
convert a String = "1;2;3;4;5;6;7;8;9;10" into an Array [1,2,3,4,5,...]
so
that I can use these values.

I've tried many a method, but can't seem to get the desired result; I've
tried gsub(/\;/, ","), eval (), and others.

##########

raw_data = "1;2;3;4;5;6;7;8;9;10"
data = raw_data.split(/\;/) #but this gives ["1", "2", "3", "4", "5",
"6", "7", "8", "9", "10"], not [1, 2, 3,...]

This is the right track, you just need to then convert each string to
a number, e.g.

raw_data.split(";").map { |raw| raw.to_i }

3

you mean something like this?

"1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

looking below, where do 11, 12 come from in the desired result?

···

raw_data = "1;2;3;4;5;6;7;8;9;10"
data = raw_data.split(/\;/) #but this gives ["1", "2", "3", "4", "5",
"6", "7", "8", "9", "10"], not [1, 2, 3,...]

#data = [1,2,3,4,5,6,7,8,9,10,11,12] # this is the desired result

On Tue, Dec 28, 2010 at 5:58 PM, Thomas T. <tthackery@gmail.com> wrote:

I'm trying to convert a String of numbers that are separated by
semicolons to an Array---totally for fun, to stretch my ruby
understanding, fyi.

I use the Array in a while loop which does work when the Array looks
like = [1,2,3,4,5,...]---so that part is working. But I want to use ruby
to
convert a String = "1;2;3;4;5;6;7;8;9;10" into an Array [1,2,3,4,5,...]
so
that I can use these values.

I've tried many a method, but can't seem to get the desired result; I've
tried gsub(/\;/, ","), eval (), and others.

##########

raw_data = "1;2;3;4;5;6;7;8;9;10"
data = raw_data.split(/\;/) #but this gives ["1", "2", "3", "4", "5",
"6", "7", "8", "9", "10"], not [1, 2, 3,...]

#data = [1,2,3,4,5,6,7,8,9,10,11,12] # this is the desired result

boundary = 1
ending_boundary = 13
interval = (ending_boundary - boundary)/3

while boundary < ending_boundary
   print "For the class #{boundary} to #{boundary + interval}, "
   print "the group is: "
   puts data.select{ |x| x >= boundary && x < (boundary + interval)
}.size
   print data.select{ |x| x >= boundary && x < (boundary + interval)
}.join(' ')
   boundary = boundary + interval #increase the boundary to the next
class
   print ".\n"
end

--
Posted via http://www.ruby-forum.com/\.

4

Thanks to both. I'm reading up on these methods you've supplied at
http://www.ruby-doc.org/core/\. It looks like the .map method is a
synonym for .collect. I'll read up on .inject next.

you mean something like this?

"1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Yes. In fact, both of these work---liking ruby's flexibility here.

#data = raw_data.split(/\;/).map { |raw| raw.to_f}
#data = raw_data.split(/\;/).inject() { |a,i| a << i.to_f }

looking below, where do 11, 12 come from in the desired result? my

inconsistency.

Thomas

···

--
Posted via http://www.ruby-forum.com/\.

5

Ian M. Asaff wrote in post #971169:

you mean something like this?
"1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Ok, I've read the page on .inject, but do have a question on your
solution. I'm interested in the where I read an initial value may be
supplied in .inject(). Is the initializing an empty array to which
the accumulator, a, will populate?

···

--
Posted via http://www.ruby-forum.com/\.

6

Yep.

--sent from myu droid. typoos courtesy of droid's crappy keyboarsd

···

On Dec 28, 2010 6:41 PM, "Thomas T." <tthackery@gmail.com> wrote:

Ian M. Asaff wrote in post #971169:

you mean something like this?
"1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Ok, I've read the page on .inject, but do have a question on your
solution. I'm interested in the where I read an initial value may be
supplied in .inject(). Is the initializing an empty array to which
the accumulator, a, will populate?

--
Posted via http://www.ruby-forum.com/\.

7

Go with map, this is its raison d'etre.

···

On Tue, Dec 28, 2010 at 5:19 PM, Thomas T. <tthackery@gmail.com> wrote:

Thanks to both. I'm reading up on these methods you've supplied at
http://www.ruby-doc.org/core/\. It looks like the .map method is a
synonym for .collect. I'll read up on .inject next.

> you mean something like this?
>
> "1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
> => [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>

Yes. In fact, both of these work---liking ruby's flexibility here.

#data = raw_data.split(/\;/).map { |raw| raw.to_f}
#data = raw_data.split(/\;/).inject() { |a,i| a << i.to_f }

8

I would avoid the inject solution because it's cumbersome and isn't as easy
to understand; map is pretty much to-the-point and doesn't have this weird
empty-array accumulator. The inject solution is just reinventing the map
wheel.

···

On Tue, Dec 28, 2010 at 6:43 PM, Ian M. Asaff <ian.asaff@gmail.com> wrote:

Yep.

--sent from myu droid. typoos courtesy of droid's crappy keyboarsd
On Dec 28, 2010 6:41 PM, "Thomas T." <tthackery@gmail.com> wrote:
> Ian M. Asaff wrote in post #971169:
>> you mean something like this?
>> "1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
>> => [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>
> Ok, I've read the page on .inject, but do have a question on your
> solution. I'm interested in the where I read an initial value may be
> supplied in .inject(). Is the initializing an empty array to which
> the accumulator, a, will populate?
>
> --
> Posted via http://www.ruby-forum.com/\.
>

9

Thank you all for your assistance. Calling the .methods on a string like
I had was rather overwhelming, and many of the RDoc definitions are
still opaque to me.

···

--
Posted via http://www.ruby-forum.com/.

10

How about this?

eval("[" + "1;2;3".gsub(/;/,',') + "]")
=> [1,2,3]

Masa

···

2010/12/29 Adam Prescott <mentionuse@gmail.com>:

I would avoid the inject solution because it's cumbersome and isn't as easy
to understand; map is pretty much to-the-point and doesn't have this weird
empty-array accumulator. The inject solution is just reinventing the map
wheel.

On Tue, Dec 28, 2010 at 6:43 PM, Ian M. Asaff <ian.asaff@gmail.com> wrote:

Yep.

--sent from myu droid. typoos courtesy of droid's crappy keyboarsd
On Dec 28, 2010 6:41 PM, "Thomas T." <tthackery@gmail.com> wrote:
> Ian M. Asaff wrote in post #971169:
>> you mean something like this?
>> "1;2;3;4;5;6;7;8;9;10".split(';').inject() { |a,i| a << i.to_i }
>> => [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>
> Ok, I've read the page on .inject, but do have a question on your
> solution. I'm interested in the where I read an initial value may be
> supplied in .inject(). Is the initializing an empty array to which
> the accumulator, a, will populate?
>
> --
> Posted via http://www.ruby-forum.com/\.
>