How to Convert String to Array

Hey everyone,

Newb question: I want to read the user input an array of numbers. Is
this possible? If not, then I want to convert the string input (from
gets) into an array.

For example:

user inputs [5,3,46,6,5]
gets.chomp converts this to a string "[5,3,46,6,5]"
I want [5,3,46,6,5] (the arrray, not the string)

Any help would be greatly appreciated.

Thanks,

~sphoenixee~

···

--
Posted via http://www.ruby-forum.com/.

irb(main):017:0> x = '[5,3,46,6,5]'
=> "[5,3,46,6,5]"
irb(main):018:0> y = x[1..-2].split(',').collect! {|n| n.to_i}
=> [5, 3, 46, 6, 5]
irb(main):019:0>

1. x[1..-2] is the string without the brackets.
2. split(',') splits the string at commas into an array of strings.
3. collect! calls .to_i on each string in the array and replaces the
string with the result of the conversion.

···

On Mar 23, 6:36 pm, Shengzhi Li <shengz...@gmail.com> wrote:

Hey everyone,

Newb question: I want to read the user input an array of numbers. Is
this possible? If not, then I want to convert the string input (from
gets) into an array.

For example:

user inputs [5,3,46,6,5]
gets.chomp converts this to a string "[5,3,46,6,5]"
I want [5,3,46,6,5] (the arrray, not the string)

Any help would be greatly appreciated.

Thanks,

~sphoenixee~

--
Posted viahttp://www.ruby-forum.com/.

a = "[5,3,46,6,5]"
a.gsub!(/[\[\]]/,'').split(/\s*,\s*/)
=> ["5", "3", "46", "6", "5"]

This removes the first, then splits on ,

-d

···

On Sat, Mar 24, 2007 at 07:36:31AM +0900, Shengzhi Li wrote:

Hey everyone,

Newb question: I want to read the user input an array of numbers. Is
this possible? If not, then I want to convert the string input (from
gets) into an array.

For example:

user inputs [5,3,46,6,5]
gets.chomp converts this to a string "[5,3,46,6,5]"
I want [5,3,46,6,5] (the arrray, not the string)

irb(main):001:0> s = "[5,3,46,6,5]"
=> "[5,3,46,6,5]"
irb(main):002:0> a = s.scan( /\d+/ )
=> ["5", "3", "46", "6", "5"]
irb(main):003:0> a.map!{ |s| s.to_i }
=> [5, 3, 46, 6, 5]

···

On Mar 23, 4:36 pm, Shengzhi Li <shengz...@gmail.com> wrote:

Hey everyone,

Newb question: I want to read the user input an array of numbers. Is
this possible? If not, then I want to convert the string input (from
gets) into an array.

For example:

user inputs [5,3,46,6,5]
gets.chomp converts this to a string "[5,3,46,6,5]"
I want [5,3,46,6,5] (the arrray, not the string)

Sure:

$ ruby -rubygems read_array.rb
Enter some numbers:
1
2
3

You entered: [1, 2, 3]
$ cat read_array.rb
#!/usr/bin/env ruby -w

require "highline/import"

array = ask("Enter some numbers:", lambda { |n| Integer(n) rescue n }) do |q|
   q.gather = String.new
end
puts "You entered: #{array.inspect}"

__END__

Hope that helps.

James Edward Gray II

···

On Mar 23, 2007, at 5:36 PM, Shengzhi Li wrote:

Newb question: I want to read the user input an array of numbers. Is
this possible?

Amazing guys, a question posted in 2007 is still helping successfully to
beginners.
Thanks to all.

···

--
Posted via http://www.ruby-forum.com/.

> Hey everyone,
>
> Newb question: I want to read the user input an array of numbers. Is
> this possible? If not, then I want to convert the string input (from
> gets) into an array.
>
> For example:
>
> user inputs [5,3,46,6,5]
> gets.chomp converts this to a string "[5,3,46,6,5]"
> I want [5,3,46,6,5] (the arrray, not the string)

a = "[5,3,46,6,5]"
a.gsub!(/[\[\]]/,'').split(/\s*,\s*/)
=> ["5", "3", "46", "6", "5"]

This removes the first, then splits on ,

missed the collect as mentioned in the other response.

···

On Sat, Mar 24, 2007 at 07:51:27AM +0900, Daniel wrote:

On Sat, Mar 24, 2007 at 07:36:31AM +0900, Shengzhi Li wrote:

-d

--
"You will never know how much it has cost my generation to preserve your
freedom. I hope you will make good use of it." -- John Quincy Adams

"Yes, we did produce a near-perfect republic. But will they keep it? Or will
they, in the enjoyment of plenty, lose the memory of freedom? Material
abundance without character is the path of destruction." -- Thomas Jefferson

Or then again:

x = eval("[5,3,46,6,5]" )

x is now an array!

best wishes
Huw Collingbourne

http://www.sapphiresteel.com
Ruby Programming In Visual Studio 2005

require 'yaml'
some_obj = YAML.load(gets.chomp) rescue nil

If your input is "[1,2,3,4]" then it will return an array with 4
elements of 1, 2, 3 and 4, respectively. Of course, you could input
any valid (or not so valid) YAML and get back a String or Hash or....
The rescue is just to ensure we get a nil instead of an error on
really bad input.

Enjoy,
Paul

Huw Collingbourne wrote:

Or then again:

x = eval("[5,3,46,6,5]" )

x is now an array!

Unless the user actually entered something like `rm -rf /` instead of [5,3,46,6,5] :wink:

···

best wishes
Huw Collingbourne

http://www.sapphiresteel.com
Ruby Programming In Visual Studio 2005

Easy, but not safe if you are accepting arbitrary input from a user.

x = eval("`rm -rf .`")

···

On 3/23/07, Huw Collingbourne <huw@delthisbitdarkneon.com> wrote:

Or then again:

x = eval("[5,3,46,6,5]" )

x is now an array!

--
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denhaven2.com/

I didn't know that yaml can contain bracketed arrays like this. However, your
code seems to work only if there are spaces along with the comas :

irb(main):012:0> YAML.load("[1, 2, 3]")
=> [1, 2, 3]

but

irb(main):013:0> YAML.load("[1,2,3]")
=> [123]

···

Le samedi 24 mars 2007 00:20, Paul Stickney a écrit :

require 'yaml'
some_obj = YAML.load(gets.chomp) rescue nil

If your input is "[1,2,3,4]" then it will return an array with 4
elements of 1, 2, 3 and 4, respectively. Of course, you could input
any valid (or not so valid) YAML and get back a String or Hash or....
The rescue is just to ensure we get a nil instead of an error on
really bad input.

Enjoy,
Paul

--
Olivier Renaud

Thanks for the correction Olivier, you are indeed correct.
I didn't realize the whitespace made a difference :-/

Wow, I never knew there'd be so many ways to do it! Thanks so much to
all who replied! I really appreciate it.

sphoenixee

···

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Posted via http://www.ruby-forum.com/.