Sira_PS
(Sira PS)
24 April 2011 08:02
1
If I have an array like this
["Member", "Friends", "Hello", "Components", "Family", "Lastname"]
And I need to split this array from "Components" and get 2 arrays which
are
["Member", "Friends", "Hello"]
and
["Family", "Lastname"]
Can I do that and how?
···
--
Posted via http://www.ruby-forum.com/ .
Maybe you can refer to Enumerable#slice_before
Here's a sample code:
a = ["Member","Friends","Hello","Components","Family","Lastname"]
b = a.slice_before {|elem| elem == "Components" }.to_a
p b[0] #=> ["Member", "Friends", "Hello"]
p b[1] #=> ["Components", "Family", "Lastname"]
Joey
···
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Posted via http://www.ruby-forum.com/ .
Here's a tricky one:)
a = ["Member","Friends","Hello","Components","Family","Lastname"]
b = a.partition {|elem| true unless elem=="Components"..false }
p b
#=> [["Member","Friends","Hello"], ["Components","Family",
"Lastname"]]
···
--
Posted via http://www.ruby-forum.com/ .
Sira PS wrote in post #994712:
If I have an array like this
["Member", "Friends", "Hello", "Components", "Family", "Lastname"]
And I need to split this array from "Components" and get 2 arrays which
are
["Member", "Friends", "Hello"]
and
["Family", "Lastname"]
Can I do that and how?
I think this is the simplest way:
a = ["Member", "Friends", "Hello", "Components", "Family", "Lastname"]
i = a.index("Components")
p a[0...i]
p a[i+1..-1]
···
--
Posted via http://www.ruby-forum.com/\ .
How about this?
module Enumerable
def split(sep = nil)
res = Array.new
part = Array.new
self.each do |el|
if block_given? ? yield(el) : el === sep then
res.push(part)
part = Array.new
else
part.push(el)
end
end
res.push(part)
res
end
end
ruby-1.9.2-p180 :015 > ar = ["Member", "Friends", "Hello",
"Components", "Family", "Lastname"]
=> ["Member", "Friends", "Hello", "Components", "Family", "Lastname"]
ruby-1.9.2-p180 :016 > ar.split("Friends")
=> [["Member"], ["Hello", "Components", "Family", "Lastname"]]
ruby-1.9.2-p180 :017 > ar.split do |el| el[-1] == "s" end
=> [["Member"], ["Hello"], ["Family", "Lastname"]]
···
--
Roger Braun
rbraun.net | humoralpathologie.de