What is this syntax?

ruby-talk
1

def foo(*)
end

What does the "*" mean?

2

"David Corbin" <dcorbin@machturtle.com> schrieb im Newsbeitrag news:200502131241.13403.dcorbin@machturtle.com...

def foo(*)
end

What does the "*" mean?

Any number of arguments

def foo(*) end
nil
foo 1
nil
foo
nil
foo 1,2,3
nil

Kind regards

    robert

3

And the foo method just can't refer to them?

···

On Sunday 13 February 2005 12:54 pm, Robert Klemme wrote:

"David Corbin" <dcorbin@machturtle.com> schrieb im Newsbeitrag
news:200502131241.13403.dcorbin@machturtle.com...

> def foo(*)
> end
>
> What does the "*" mean?

Any number of arguments

4

David Corbin wrote:

···

On Sunday 13 February 2005 12:54 pm, Robert Klemme wrote:

"David Corbin" <dcorbin@machturtle.com> schrieb im Newsbeitrag
news:200502131241.13403.dcorbin@machturtle.com...

def foo(*)
end

What does the "*" mean?

Any number of arguments

And the foo method just can't refer to them?

Right... I'd assume it's for some kind of case where you're
stubbing something and you want to prevent an undefined
method but you don't really care about the parameters.

Hal