I read the RDoc and it says:
For each object, directly writes *obj*.inspect followed by the current
output record separator to the program‘s standard output.
But my $\ is surely nil, it still append a newline after output.
("output record separator" is $\, right?)
Why does it do this?
--
Lai, Yu-Hsuan
Looking into Ruby 1.8.7's source code I see this in io.c:
void
rb_p(obj) /* for debug print within C code */
VALUE obj;
{
rb_io_write(rb_stdout, rb_obj_as_string(rb_inspect(obj)));
rb_io_write(rb_stdout, rb_default_rs);
}
This is the function called by the function defined as 'p'. As you can
see it's outputting the rb_default_rs. Searching for this in the
source, it's only assigned to here, in io.c:
rb_rs = rb_default_rs = rb_str_new2("\n");
So it seems it's assigned to "\n". I don't know if this rb_default_rs
is assigned to something else somewhere else (a grep -r rb_default_rs
* only shows the assignment I showed above), maybe someone with more
knowledge can chime in. If this is not the case, then I guess the
documentation should say "the default record separator". Anyone?
Jesus.
On Thu, Mar 17, 2011 at 6:02 PM, Yu-Hsuan Lai <raincolee@gmail.com> wrote:
I read the RDoc and it says:
For each object, directly writes *obj*.inspect followed by the current
output record separator to the program‘s standard output.But my $\ is surely nil, it still append a newline after output.
("output record separator" is $\, right?)
Why does it do this?
puts and p do not honor $\, print does.
Couple lines down:
rb_define_hooked_variable("$\\", &rb_output_rs, 0, rb_str_setter);
That means that rb_output_rs is hooked up to $\ and changing it in ruby will bridge to C.
On Mar 17, 2011, at 10:24 , Jesús Gabriel y Galán wrote:
On Thu, Mar 17, 2011 at 6:02 PM, Yu-Hsuan Lai <raincolee@gmail.com> wrote:
I read the RDoc and it says:
For each object, directly writes *obj*.inspect followed by the current
output record separator to the program‘s standard output.But my $\ is surely nil, it still append a newline after output.
("output record separator" is $\, right?)
Why does it do this?Looking into Ruby 1.8.7's source code I see this in io.c:
void
rb_p(obj) /* for debug print within C code */
VALUE obj;
{
rb_io_write(rb_stdout, rb_obj_as_string(rb_inspect(obj)));
rb_io_write(rb_stdout, rb_default_rs);
}This is the function called by the function defined as 'p'. As you can
see it's outputting the rb_default_rs. Searching for this in the
source, it's only assigned to here, in io.c:rb_rs = rb_default_rs = rb_str_new2("\n");
So it seems it's assigned to "\n". I don't know if this rb_default_rs
is assigned to something else somewhere else (a grep -r rb_default_rs
* only shows the assignment I showed above), maybe someone with more
knowledge can chime in. If this is not the case, then I guess the
documentation should say "the default record separator". Anyone?
DOH... Wow. I'm tired. Apparently my espresso hasn't hit the bloodstream yet. I overlooked rb_output_rs vs rb_default_rs. Xavier is right, 'p' doesn't honor $\ at all. The doco is wrong. I'll change it.
On Mar 17, 2011, at 13:59 , Ryan Davis wrote:
On Mar 17, 2011, at 10:24 , Jesús Gabriel y Galán wrote:
On Thu, Mar 17, 2011 at 6:02 PM, Yu-Hsuan Lai <raincolee@gmail.com> wrote:
I read the RDoc and it says:
For each object, directly writes *obj*.inspect followed by the current
output record separator to the program‘s standard output.But my $\ is surely nil, it still append a newline after output.
("output record separator" is $\, right?)
Why does it do this?Looking into Ruby 1.8.7's source code I see this in io.c:
void
rb_p(obj) /* for debug print within C code */
VALUE obj;
{
rb_io_write(rb_stdout, rb_obj_as_string(rb_inspect(obj)));
rb_io_write(rb_stdout, rb_default_rs);
}This is the function called by the function defined as 'p'. As you can
see it's outputting the rb_default_rs. Searching for this in the
source, it's only assigned to here, in io.c:rb_rs = rb_default_rs = rb_str_new2("\n");
So it seems it's assigned to "\n". I don't know if this rb_default_rs
is assigned to something else somewhere else (a grep -r rb_default_rs
* only shows the assignment I showed above), maybe someone with more
knowledge can chime in. If this is not the case, then I guess the
documentation should say "the default record separator". Anyone?Couple lines down:
rb_define_hooked_variable("$\\", &rb_output_rs, 0, rb_str_setter);
That means that rb_output_rs is hooked up to $\ and changing it in ruby will bridge to C.