Using yield with a recursive data structure

I am wanting to use yield on a recursive data structure. Here is a simple
example

class Fred
  def initialize(xs)
    @data = xs
  end

  def list(&block)
    @data.each do |x|
      if x.kind_of? Fred
        x.list
      else
        yield x
      end
    end
  end
end

f1 = Fred.new([1,2,3,4,5])

f1.list do |x|
  p x
end

Which as expected displays the number 1 to 5, however when I try this

f2 = Fred.new([100, f1, 200])

f2.list do |x|
  p x
end

I get 100 and "no block given (yield)" as it tries to recurse. What I am
expecting to see is 100,1,2,3,4,5,200

Any idea how I can achieve this?

As per an error you get - there's "no block given" when recursing.

You will need to replace the call `x.list` with `x.list(&block)` to pass the block.

···

On 5/6/22 15:48, Peter Hickman wrote:

I am wanting to use yield on a recursive data structure. Here is a simple example

class Fred
def initialize(xs)
@data = xs
end

def list(&block)
@data.each do |x|
if x.kind_of? Fred
x.list
else
yield x
end
end
end
end

f1 = Fred.new([1,2,3,4,5])

f1.list do |x|
p x
end

Which as expected displays the number 1 to 5, however when I try this

f2 = Fred.new([100, f1, 200])

f2.list do |x|
p x
end

I get 100 and "no block given (yield)" as it tries to recurse. What I am expecting to see is 100,1,2,3,4,5,200

Any idea how I can achieve this?

Ah, I have been completely over thinking this

Thanks for that :slight_smile:

···

On Fri, 6 May 2022 at 14:53, hmdne <hmdne@airmail.cc> wrote:

As per an error you get - there's "no block given" when recursing.

You will need to replace the call `x.list` with `x.list(&block)` to pass
the block.

On 5/6/22 15:48, Peter Hickman wrote:
> I am wanting to use yield on a recursive data structure. Here is a
> simple example
>
> class Fred
> def initialize(xs)
> @data = xs
> end
>
> def list(&block)
> @data.each do |x|
> if x.kind_of? Fred
> x.list
> else
> yield x
> end
> end
> end
> end
>
> f1 = Fred.new([1,2,3,4,5])
>
> f1.list do |x|
> p x
> end
>
> Which as expected displays the number 1 to 5, however when I try this
>
> f2 = Fred.new([100, f1, 200])
>
> f2.list do |x|
> p x
> end
>
> I get 100 and "no block given (yield)" as it tries to recurse. What I
> am expecting to see is 100,1,2,3,4,5,200
>
> Any idea how I can achieve this?

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