Ken Collins wrote:
This is possible, but it is rather cumbersome and slow, since the regexp has
to be applied to each hash key in turn until a match is found.
Maybe you could provide more detail about the problem to be solved instead
of this notion about how to solve it. Even one word more.
--
Paul Lutus
http://www.arachnoid.com
I sure could...
The hash is going to be real small. It would at most only have 3 or 4 keys. The one I want has a prefix of an arbitrary string with any amount of number after it. I need to know if this key is present so that I can run a conditional block of code. It would be a bonus to get some match data back on that last series of digits in the regexp.
I would like to use something like this:
def foobar
if hash.has_key?(/^foo_\d+$/)
...
end
end
Meanwhile my code looks like this and I was pretty sure there might be a more terse solution.
def foobar
unless params.reject{ |k, v| k !~ /^foo_\d+$/ }.empty?
...
end
end
On Oct 4, 2006, at 12:20 AM, Paul Lutus wrote:
Ken Collins wrote:
This is possible, but it is rather cumbersome and slow, since the regexp has
to be applied to each hash key in turn until a match is found.Maybe you could provide more detail about the problem to be solved instead
of this notion about how to solve it. Even one word more.--
Paul Lutus
http://www.arachnoid.com
Very postmodern!
(Does anyone get any body text in Ken's emails? I'm receiving just the
headers - and it looks like I'm not alone, judging by Paul Lutus's
earlier message.)
Paul.
On 04/10/06, Ken Collins <ken@metaskills.net> wrote:
Hi --
On Wed, 4 Oct 2006, Ken Collins wrote:
I sure could...
The hash is going to be real small. It would at most only have 3 or 4 keys. The one I want has a prefix of an arbitrary string with any amount of number after it. I need to know if this key is present so that I can run a conditional block of code. It would be a bonus to get some match data back on that last series of digits in the regexp.
I would like to use something like this:
def foobar
if hash.has_key?(/^foo_\d+$/)
...
end
I'm having trouble following this thread, because some message bodies
aren't appearing -- but the basic answer is: /.../ is itself a
potential hash key (since keys can be any object), so you have to do
something other than just hand it off to has_key? if you want to
search for a string key that matches it.
David
--
David A. Black | dblack@wobblini.net
Author of "Ruby for Rails" [1] | Ruby/Rails training & consultancy [3]
DABlog (DAB's Weblog) [2] | Co-director, Ruby Central, Inc. [4]
[1] Ruby for Rails | [3] http://www.rubypowerandlight.com
[2] http://dablog.rubypal.com | [4] http://www.rubycentral.org
I sent an new one out right after this.
It appears that my public email key being attached to the email was wiping the body for some reason.
- Ken (to reply again)
I sure could...
The hash is going to be real small. It would at most only have 3 or 4 keys. The one I want has a prefix of an arbitrary string with any amount of number after it. I need to know if this key is present so that I can run a conditional block of code. It would be a bonus to get some match data back on that last series of digits in the regexp.
I would like to use something like this:
def foobar
if hash.has_key?(/^foo_\d+$/)
...
end
end
Meanwhile my code looks like this and I was pretty sure there might be a more terse solution.
def foobar
unless params.reject{ |k, v| k !~ /^foo_\d+$/ }.empty?
...
end
end
On Oct 4, 2006, at 8:38 AM, Paul Battley wrote:
On 04/10/06, Ken Collins <ken@metaskills.net> wrote:
Very postmodern!
(Does anyone get any body text in Ken's emails? I'm receiving just the
headers - and it looks like I'm not alone, judging by Paul Lutus's
earlier message.)Paul.
Ken Collins wrote:
def foobar
unless params.reject{ |k, v| k !~ /^foo_\d+$/ }.empty?
...
end
end
Hi Ken,
How about:
def foobar(params)
if params.select { |k,v| k =~ /^foo_(\d+)$/ }
p $1
end
end
Regards,
Jordan
MonkeeSage wrote:
How about:
Actually, make that #find rather than #select, so that iteration stops
as soon as the match goes through.
Regards,
Jordan
Actually, that was very good advice, THANK YOU!
I did not even consider using an Enumerable method, I was stuck on Hash methods.
if foo_key = hash.find { |k,v| k =~ /^foo_(\d+)$/ }[0]
# Now I can use foo_key to look at the values
# I can also use $1 where needed for the match
end
Thanks again,
Ken
On Oct 4, 2006, at 9:25 AM, MonkeeSage wrote:
MonkeeSage wrote:
How about:
Actually, make that #find rather than #select, so that iteration stops
as soon as the match goes through.Regards,
Jordan