Hi,
I need to truncate some Floats and found this:
http://www.approximity.com/cgi-bin/blogtariAgile/index.rb/+Forth/RetroWeb.rdoc
It suggests:
class Float
def truncate(sd=2)
scale=(10**sd).to_f
(self * scale).to_i / scale
end
end
a=0.255
a.truncate(2) #-> 0.25
Is there a better way to do the above? I'm sort of surprised that there
isn't a builtin, but perhaps I'm not looking in the right place.
Thanks,
Keith
Probably cause you can do it in one line:
('%.2f' % 0.255).to_f
Probably cause you can do it in one line:
('%.2f' % 0.255).to_f
That's rounding, not truncating.
For some purposes, there's BigDecimal, where x.yz is really two decimals
(and not an approximation as a flost takes)
And behold! BigDecimal#floor takes an argument, the number of digits you
want (had to look that up myself; learn something new every day 
+--- Kero ------------------------- kero@chello@nl ---+
all the meaningless and empty words I spoke |
Promises -- The Cranberries |
+--- M38c --- http://members.chello.nl/k.vangelder ---+
Okay, how about:
0.255.to_s.sub(/(\.\d{2})\d+/, "\\1").to_f
James Edward Gray II
On Oct 1, 2005, at 4:31 AM, Kero wrote:
Probably cause you can do it in one line:
('%.2f' % 0.255).to_f
That's rounding, not truncating.
for more enjoyment and greater efficiency:
(s=2.33333.to_s + "00").slice(0,s.index(".")+3)
"James Edward Gray II" <james@grayproductions.net> wrote in message
news:AF6D1EBB-D94C-40C7-913E-CE6137D99FFA@grayproductions.net...
On Oct 1, 2005, at 4:31 AM, Kero wrote:
Probably cause you can do it in one line:
('%.2f' % 0.255).to_f
That's rounding, not truncating.
Okay, how about:
0.255.to_s.sub(/(\.\d{2})\d+/, "\\1").to_f
James Edward Gray II