Is there any function in ruby which allows you to trim leading zeros (or
any specific character) from a string. Or if there is some reg
expression that i can use?
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Posted via http://www.ruby-forum.com/.
Is there any function in ruby which allows you to trim leading zeros (or
any specific character) from a string. Or if there is some reg
expression that i can use?
--
Posted via http://www.ruby-forum.com/.
Hi,
for simple character replacement, you may do something like
"####helloworld".gsub!(/^#+/,'')
the same can be written in String class if you use this too often,
class String
def trim_lead(n)
self.gsub!(/^#{n}+/,'')
end
end
puts "00001234".trim_lead("0")
but when you use this to replace any special characters used
internally by regex (for e.g., $)
you have to do something like "$$$1234".trim_lead("\\$")
Others may suggest better ways.
On Dec 29, 5:00 pm, Dipesh Batheja <dipesh_bath...@yahoo.com> wrote:
Is there any function in ruby which allows you to trim leading zeros (or
any specific character) from a string. Or if there is some reg
expression that i can use?
--
Posted viahttp://www.ruby-forum.com/.
Dipesh Batheja wrote:
Is there any function in ruby which allows you to trim leading zeros (or
any specific character) from a string. Or if there is some reg
expression that i can use?
Hi
if you have string expressions like
s = 0{1,*}[1-9]* (some number with leading zeros)
perhaps the must obvious method is
s.to_i.to_s
but this isn't genralizable to other kind of leading characters,
for them a regexp may be better
Tom
The simplest and fastest is probably
s.sub! /\A0+/, ''
Kind regards
robert
On 29.12.2007 13:00, Dipesh Batheja wrote:
Is there any function in ruby which allows you to trim leading zeros (or
any specific character) from a string. Or if there is some reg
expression that i can use?