Strings and ranges

ruby-talk
1

“David A. Black”
<dblack@wobblini To: ruby-talk@ruby-lang.org (ruby-talk ML)
.net> cc:
12/03/2003 10:48
AM
Please respond
to ruby-talk

Hi –

The following program doesn’t execute as I would expect:

#!/usr/bin/ruby

stringy = “X”

1.upto(10) do |i|
puts stringy
stringy.succ!
end

“X”.upto(“AG”) do |ss|
puts ss
end

puts “‘AB’ > ‘AA’ = #{‘AB’ > ‘AA’}”
puts “‘X’ < ‘AA’ = #{‘X’ < ‘AB’}”

Interesting – just like “9” and “10” (i.e., “9” > “9”.succ).

The code below gets around my problem…

stringy = “X”
while true
puts stringy
stringy.succ!
break if stringy == “AH”
end

Is there a better way?

How about this:

x = “X”
puts (0…10).map { x.succ! .dup }

(You need the .dup or you’ll end up with 10 of x, all the same
string.)

···

Subject: Re: strings and ranges
On Thu, 4 Dec 2003 charlie.mills@milliman.com wrote:

–
That works.
I guess I also want to capture the ability to iterate until you reach a
given string.
So the problem with going through the range 0…10 is you have to have a
way of mapping “X” to 0 and “AG” to 10 (or to two numbers whose difference
is 10).
(I guess you also have to know that “Z”.succ → “AA”, and that “X” and “AG”
are of the form /[A-Z]+/)

-Charlie

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