Hi
Tthere is no string.uniq ?!?
Whats the best way to do this?
Opti
string.split('').uniq.join('') perhaps?
···
On 4/23/22 07:57, Die Optimisten wrote:
Hi
Tthere is no string.uniq ?!?
Whats the best way to do this?Opti
Thank you, I thought of sg like that.
Another thing:
How to (best) subtract arrays that way:
a=[1,2,2,3,3], b=[1,2,3,3,4,4] => a-b = [1,2] # count is relevant
## easier way than hash with counts?
and optional: also retourning $underflow=[4,4]
# shouldn't that be added (arr-arr2 is not a set!)
Opti
Try this:
'this_is_your_string_it_is'.chars.uniq.join
==>"this_yourng"
···
On Fri, Apr 22, 2022 at 11:02 PM hmdne <hmdne@airmail.cc> wrote:
string.split('').uniq.join('') perhaps?
On 4/23/22 07:57, Die Optimisten wrote:
> Hi
>
> Tthere is no string.uniq ?!?
> Whats the best way to do this?
>
> Opti
>Unsubscribe: <mailto:ruby-talk-request@ruby-lang.org?subject=unsubscribe>
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Why should there be?!?
···
On Apr 22, 2022, at 22:58, Die Optimisten <inform@die-optimisten.net> wrote:
Tthere is no string.uniq ?!?
Hi,
To answer your first question, just do this:
str.chars.uniq.join
To answer your second question about subtracting arrays, perhaps you meant
to find the intersection of the arrays?
[1,2,2,3,3] & [1,2,3,3,4,4] # => [1,2,3]
To detect extra elements, do `b - a` (that returns `[4, 4]`) or `(b - a) +
(a - b)` for both sides if a has elements not in b too.
Cheers!
···
On Sun, Apr 24, 2022 at 5:10 AM Ryan Davis <ryand-ruby@zenspider.com> wrote:
> On Apr 22, 2022, at 22:58, Die Optimisten <inform@die-optimisten.net> > wrote:
>
> Tthere is no string.uniq ?!?Why should there be?!?
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