eg: str = "a b c d"
newStr = str.sub(" ", ", ")
gives me output a, b c d
what i want is a, b, c, d
ow do i make this happen sub isnt doing it for me i guess. I been
looking all through the ruby-doc to no avail.
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Hi --
On Mon, 29 Sep 2008, Nick Bo wrote:
eg: str = "a b c d"
newStr = str.sub(" ", ", ")gives me output a, b c d
what i want is a, b, c, d
ow do i make this happen sub isnt doing it for me i guess. I been
looking all through the ruby-doc to no avail.
Check out String#gsub, and also Array#join.
David
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Advancing with Rails January 19-22 Fort Lauderdale, FL *
* Co-taught with Patrick Ewing!
See http://www.rubypal.com for details and updates!
try gsub instead of sub.
Jamey
On Sun, Sep 28, 2008 at 9:04 PM, Nick Bo <bornemann1@nku.edu> wrote:
eg: str = "a b c d"
newStr = str.sub(" ", ", ")gives me output a, b c d
what i want is a, b, c, d
ow do i make this happen sub isnt doing it for me i guess. I been
looking all through the ruby-doc to no avail.
--
Posted via http://www.ruby-forum.com/\.
You want to use str.gsub rather than str.sub. Compare the documentation of the two:
------------------------------------------------------------ String#gsub
str.gsub(pattern, replacement) => new_str
str.gsub(pattern) {|match| block } => new_str
From Ruby 1.9.0
On Sep 28, 2008, at 9:04 PM, Nick Bo wrote:
eg: str = "a b c d"
newStr = str.sub(" ", ", ")gives me output a, b c d
what i want is a, b, c, d
ow do i make this happen sub isnt doing it for me i guess. I been
looking all through the ruby-doc to no avail.
------------------------------------------------------------------------
Returns a copy of _str_ with _all_ occurrences of _pattern_
replaced with either _replacement_ or the value of the block. The
_pattern_ will typically be a +Regexp+; if it is a +String+ then no
regular expression metacharacters will be interpreted (that is
+/\d/+ will match a digit, but +'\d'+ will match a backslash
followed by a 'd').
[...]
------------------------------------------------------------- String#sub
str.sub(pattern, replacement) => new_str
str.sub(pattern) {|match| block } => new_str
From Ruby 1.9.0
------------------------------------------------------------------------
Returns a copy of _str_ with the _first_ occurrence of _pattern_
replaced with either _replacement_ or the value of the block. The
_pattern_ will typically be a +Regexp+; if it is a +String+ then no
regular expression metacharacters will be interpreted (that is
+/\d/+ will match a digit, but +'\d'+ will match a backslash
followed by a 'd').
[...]
Hope this helps,
Mike
--
Mike Stok <mike@stok.ca>
http://www.stok.ca/~mike/
The "`Stok' disclaimers" apply.
Nick Bo wrote:
eg: str = "a b c d"
newStr = str.sub(" ", ", ")gives me output a, b c d
what i want is a, b, c, d
ow do i make this happen sub isnt doing it for me i guess. I been
looking all through the ruby-doc to no avail.
gsub
--
RMagick: http://rmagick.rubyforge.org/
perfect thanks
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