Shortest if Assignment Statement

ruby-talk
1

hsh = { '*' => '(*)' , 'a' => '(1){2}' }
val = "b"
a = hsh[ val ] or hsh['*'] #to give me, a = '(*)'
val = "a"
a = hsh[ val ] or hsh['*'] #to give me, a = '(1){2}'

Not a generic answer, but in this case why don't you use Hash#default ?

2

Mehr, Assaph (Assaph) wrote:

hsh = { '*' => '(*)' , 'a' => '(1){2}' }
val = "b"
a = hsh[ val ] or hsh['*'] #to give me, a = '(*)'
val = "a"
a = hsh[ val ] or hsh['*'] #to give me, a = '(1){2}'
   
Not a generic answer, but in this case why don't you use Hash#default ?

Ah, beautiful! I didn't even know I could do a thing like that. Thanks Assaph,

Zach