Short solution for replacing Strings inside a file?

ruby-talk
1

Hello, i'm working with ruby 1.8.5 on a Suse SLES 9 Linux machine.

I need to replace strings inside files, specifically the string
FECHAIMPRE
with the current date. I had a bash script that looked like this:

BOF#################################################################
    date=`date '+%d:%m:%y'`
    for item in `ls /u/sag/impresion/PRODISAA/etiquetas/lpt28*.tmp`
    do
       sed -e s/FECHAIMPRE/$date/g < $item > $item.po
       mv $item.po $item
    done
EOF#################################################################

And i wanted to rewrite it in ruby. I came up with this:

#BOF#################################################################
$fecha= Time.now.strftime("%d/%m/%Y")

def UpdateDates(file)

    filename= file.to_s

    # Rename "file" to "file.temp"
    FileUtils.mv(filename, filename + ".temp")

    # Create "file" file
    File.open(filename, "w") do |out|

        # Write in "file" the modified "file.temp" lines.
        IO.foreach(filename + ".temp") do |line|

            if line =~ /FECHAIMPRE/
                line.gsub!(/FECHAIMPRE/, $fecha)
            end

            out << line
        end

    end

    # Erase the temporal
    FileUtils.rm(filename + ".temp", :force => true)
end

Dir.glob("*.tmp").each { |file| UpdateDates(file) }

#EOF#################################################################

But i keep thinking there has to be a shorter way. I read the ruby
documentation
for IO and File classes but i haven't found any better solution.

What do you think about it???

Thanks!

···

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Posted via http://www.ruby-forum.com/.

2

untested so try it out with another file because -i.bak does in place replacement.

ruby -i.bak -p -e "gsub! /FECHAIMPRE/, `date '+%d:%m:%y'`" /u/sag/impresion/PRODISAA/etiquetas/lpt28*.tmp

Kind regards

  robert

···

On 29.01.2007 15:39, Emmanuel wrote:

Hello, i'm working with ruby 1.8.5 on a Suse SLES 9 Linux machine.

I need to replace strings inside files, specifically the string
FECHAIMPRE
with the current date. I had a bash script that looked like this:

BOF#################################################################
    date=`date '+%d:%m:%y'`
    for item in `ls /u/sag/impresion/PRODISAA/etiquetas/lpt28*.tmp`
    do
       sed -e s/FECHAIMPRE/$date/g < $item > $item.po
       mv $item.po $item
    done
EOF#################################################################

And i wanted to rewrite it in ruby. I came up with this:

#BOF#################################################################
$fecha= Time.now.strftime("%d/%m/%Y")

def UpdateDates(file)

    filename= file.to_s

    # Rename "file" to "file.temp"
    FileUtils.mv(filename, filename + ".temp")

    # Create "file" file
    File.open(filename, "w") do |out|

        # Write in "file" the modified "file.temp" lines.
        IO.foreach(filename + ".temp") do |line|

            if line =~ /FECHAIMPRE/
                line.gsub!(/FECHAIMPRE/, $fecha)
            end

            out << line
        end

    end

    # Erase the temporal
    FileUtils.rm(filename + ".temp", :force => true)
end

Dir.glob("*.tmp").each { |file| UpdateDates(file) }

#EOF#################################################################

But i keep thinking there has to be a shorter way. I read the ruby
documentation
for IO and File classes but i haven't found any better solution.

What do you think about it???

Thanks!

3

Alle 15:39, lunedì 29 gennaio 2007, Emmanuel ha scritto:

Hello, i'm working with ruby 1.8.5 on a Suse SLES 9 Linux machine.

I need to replace strings inside files, specifically the string
FECHAIMPRE
with the current date. I had a bash script that looked like this:

BOF#################################################################
    date=`date '+%d:%m:%y'`
    for item in `ls /u/sag/impresion/PRODISAA/etiquetas/lpt28*.tmp`
    do
       sed -e s/FECHAIMPRE/$date/g < $item > $item.po
       mv $item.po $item
    done
EOF#################################################################

And i wanted to rewrite it in ruby. I came up with this:

#BOF#################################################################
$fecha= Time.now.strftime("%d/%m/%Y")

def UpdateDates(file)

    filename= file.to_s

    # Rename "file" to "file.temp"
    FileUtils.mv(filename, filename + ".temp")

    # Create "file" file
    File.open(filename, "w") do |out|

        # Write in "file" the modified "file.temp" lines.
        IO.foreach(filename + ".temp") do |line|

            if line =~ /FECHAIMPRE/
                line.gsub!(/FECHAIMPRE/, $fecha)
            end

            out << line
        end

    end

    # Erase the temporal
    FileUtils.rm(filename + ".temp", :force => true)
end

Dir.glob("*.tmp").each { |file| UpdateDates(file) }

#EOF#################################################################

But i keep thinking there has to be a shorter way. I read the ruby
documentation
for IO and File classes but i haven't found any better solution.

What do you think about it???

Thanks!

This should work (beware, it's untested).

fecha= Time.now.strftime("%d/%m/%Y")

Dir.glob("*.tmp").each do |filename|
  text=File.read filename
  File.open(filename,'w'){|f| f.write text.gsub(/FECHAIMPRE/,$fecha)}
end

Stefano

4

Stefano:
    your way worked very well, thank you!

Robert:
    I have prolems with your code, i think is because of the way my
bourne shell is interpreting the comand line. Beside, i prefer to code
the solution
inside my current script (it does another things). I don't want to quote
your code in backticks because i think that would spawn two ruby
interpreters
for this simple task.

Thank for you both!

···

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