Ruby idiom for all matches in a string

ruby-talk
1

What’s the ruby idiom for all the matches in a string.

x=“ABA ABBBA CBBA”
/A(B+)/.match(x)

Ultimately, I want to get [ “B”, “BBB” ]

Thanks

···

–
David Corbin dcorbin@machturtle.com

2

/A(B+)/.match(x).captures

Gavin

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On Monday, October 13, 2003, 8:34:41 AM, David wrote:

What’s the ruby idiom for all the matches in a string.

x=“ABA ABBBA CBBA”
/A(B+)/.match(x)

Ultimately, I want to get [ “B”, “BBB” ]

Thanks

3

Hi –

What’s the ruby idiom for all the matches in a string.

x=“ABA ABBBA CBBA”
/A(B+)/.match(x)

Ultimately, I want to get [ “B”, “BBB” ]

Thanks

/A(B+)/.match(x).captures

That won’t do it; it only gets the first one. To get them all, you
can use String#scan:

irb(main):008:0> x

“ABA ABBBA CBBA”
irb(main):009:0> x.scan(/A(B+)/)
=> [[“B”], [“BBB”]]

The reason you get an array-of-arrays (which you may have to flatten
before it’s useful) is that each scan (i.e., each application of the
regex) generates a new array of captures. (This starts to look less
cumbersome when you’ve got more than one capture.) Also, #scan takes
a block, which can be handy.

David

···

On Mon, 13 Oct 2003, Gavin Sinclair wrote:

On Monday, October 13, 2003, 8:34:41 AM, David wrote:

–
David Alan Black
home: dblack@superlink.net
work: blackdav@shu.edu
Web: http://pirate.shu.edu/~blackdav