Hi,
I'm having some strange result from the .scan method used on a string.
Here's my code :
a = "counter-46382764"
r = /counter-(\d+)/
puts (a.scan(r)).inspect
It prints : [ [ "46382764" ] ]
I was expecting : [ "46382764" ]
(just a simple array not an array in an array)
What's wrong with me ? 
Thanks a lot !
pollop.
--
Posted via http://www.ruby-forum.com/.
I'm having some strange result from the .scan method used on a string.
Here's my code :
a = "counter-46382764"
r = /counter-(\d+)/puts (a.scan(r)).inspect
It prints : [ [ "46382764" ] ]
I was expecting : [ "46382764" ]
(just a simple array not an array in an array)What's wrong with me ?
Besides not reading the documentation, probably nothing. 
% irb
"counter-46382764".scan(/counter-(\d+)/)
=> [["46382764"]]
"counter-46382764".scan(/counter-\d+/)
=> ["counter-46382764"]
"counter-46382764".scan(/\d+/)
=> ["46382764"]
ri "String.scan"
= String.scan
(from ruby core)
On Feb 21, 2011, at 13:10 , John Doe wrote:
------------------------------------------------------------------------------
str.scan(pattern) => array
str.scan(pattern) {|match, ...| block } => str
------------------------------------------------------------------------------
Both forms iterate through str, matching the pattern (which may be a
Regexp or a String). For each match, a result is generated and either added to
the result array or passed to the block. If the pattern contains no groups,
each individual result consists of the matched string, $&. If the pattern
contains groups, each individual result is itself an array containing one
entry per group.
a = "cruel world"
a.scan(/\w+/) #=> ["cruel", "world"]
a.scan(/.../) #=> ["cru", "el ", "wor"]
a.scan(/(...)/) #=> [["cru"], ["el "], ["wor"]]
a.scan(/(..)(..)/) #=> [["cr", "ue"], ["l ", "wo"]]
And the block form:
a.scan(/\w+/) {|w| print "<<#{w}>> " }
print "\n"
a.scan(/(.)(.)/) {|x,y| print y, x }
print "\n"
produces:
<<cruel>> <<world>>
rceu lowlr
