Regular expression,

ruby-talk
1

hi

"M.raja.gopalan".gsub(/(.*)\./,'')

It gives gopalan as output, but I need to replace until first "."
(i.e)output would be raja.gopalan.

How would I do this?

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2

Use "sub", and the non-greedy operator: "?"

"M.raja.gopalan".sub(/(.*?)\./,'')

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3

Thank you Joel Pearson

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4

hi Rob Biedenharn

OK, thank you.

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5

Alternatively, you could match all non-. characters up to the first . using:

"M.raja.gopalan".sub(/\A[^.]*\./,'')

\A anchors the match to the beginning of the string
[^.] matches any character that isn't a .

irb2.0.0> "M.raja.gopalan".sub(/\A[^.]*\./,'')
#2.0.0 => "raja.gopalan"

-Rob

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On 2013-Dec-18, at 04:23 , Joel Pearson <lists@ruby-forum.com> wrote:

Use "sub", and the non-greedy operator: "?"

"M.raja.gopalan".sub(/(.*?)\./,'')

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