Your problem is that '*' is greedy so it'll match as many 'any characters' as it can. Try
/.*?(\d+).*?(\d+).*?(\d+)/
Usually I'd tend to use something like:
/[^\d]*(\d+)[^\d]*(\d+)[^\d]*(\d+)/
instead, to make it explicit I want not digits, followed by digits, etc...
Hope that helps,
Ross
···
On Wed, 21 Dec 2005 18:03:13 -0000, DeZo <nobody@nowhere.com> wrote:
Why does the following code:
line = " rows = 10 cols = 1 occupied cells = 0"
line =~ /.*(\d+).*(\d+).*(\d+)/
print(" scanned rows = ",$1," cols = ",$2," occ = ",$3,"\n")
print this when it runs:
scanned rows = 0 cols = 1 occ = 0
(notice rows is zero!)
What have I done wrong?
--
Ross Bamford - rosco@roscopeco.remove.co.uk
Robert
(Robert)
2
Ross Bamford wrote:
Why does the following code:
line = " rows = 10 cols = 1 occupied cells = 0"
line =~ /.*(\d+).*(\d+).*(\d+)/
print(" scanned rows = ",$1," cols = ",$2," occ = ",$3,"\n")
print this when it runs:
scanned rows = 0 cols = 1 occ = 0
(notice rows is zero!)
What have I done wrong?
Your problem is that '*' is greedy so it'll match as many 'any
characters' as it can. Try
/.*?(\d+).*?(\d+).*?(\d+)/
Usually I'd tend to use something like:
/[^\d]*(\d+)[^\d]*(\d+)[^\d]*(\d+)/
instead, to make it explicit I want not digits, followed by digits,
etc...
Some other solutions with individual pros and cons:
line = " rows = 10 cols = 1 occupied cells = 0"
=> " rows = 10 cols = 1 occupied cells = 0"
line.scan(/\d+/)
=> ["10", "1", "0"]
line.scan(/\d+/).map {|s| s.to_i}
=> [10, 1, 0]
line.scan(/\w+\s*=\s*(\d+)/)
=> [["10"], ["1"], ["0"]]
line.scan(/\w+\s*=\s*(\d+)/).map {|m| m[0].to_i}
=> [10, 1, 0]
And explicitely matching the pattern:
/rows\s*=\s*(\d+)\s*cols\s*=\s*(\d+)\s*occupied cells\s*=\s*(\d+)/ =~
line and [$1, $2, $3]
=> ["10", "1", "0"]
/rows\s*=\s*(\d+)\s*cols\s*=\s*(\d+)\s*occupied cells\s*=\s*(\d+)/ =~
line and [$1.to_i, $2.to_i, $3.to_i]
=> [10, 1, 0]
Kind regards
robert
···
On Wed, 21 Dec 2005 18:03:13 -0000, DeZo <nobody@nowhere.com> wrote:
Ahh, much better. Another KISS reminder gets it's own page (again) in my notebook..
Thanks 
···
On Thu, 22 Dec 2005 09:42:00 -0000, Robert Klemme <bob.news@gmx.net> wrote:
Ross Bamford wrote:
On Wed, 21 Dec 2005 18:03:13 -0000, DeZo <nobody@nowhere.com> wrote:
Why does the following code:
line = " rows = 10 cols = 1 occupied cells = 0"
line =~ /.*(\d+).*(\d+).*(\d+)/
print(" scanned rows = ",$1," cols = ",$2," occ = ",$3,"\n")
print this when it runs:
scanned rows = 0 cols = 1 occ = 0
(notice rows is zero!)
What have I done wrong?
Your problem is that '*' is greedy so it'll match as many 'any
characters' as it can. Try
/.*?(\d+).*?(\d+).*?(\d+)/
Usually I'd tend to use something like:
/[^\d]*(\d+)[^\d]*(\d+)[^\d]*(\d+)/
instead, to make it explicit I want not digits, followed by digits,
etc...
Some other solutions with individual pros and cons:
line = " rows = 10 cols = 1 occupied cells = 0"
=> " rows = 10 cols = 1 occupied cells = 0"
line.scan(/\d+/)
=> ["10", "1", "0"]
line.scan(/\d+/).map {|s| s.to_i}
=> [10, 1, 0]
line.scan(/\w+\s*=\s*(\d+)/)
=> [["10"], ["1"], ["0"]]
line.scan(/\w+\s*=\s*(\d+)/).map {|m| m[0].to_i}
=> [10, 1, 0]
--
Ross Bamford - rosco@roscopeco.remove.co.uk
Jim5
(Jim)
4
I've been using this idiom recently.
line = " rows = 10 cols = 1 occupied cells = 0"
=> " rows = 10 cols = 1 occupied cells = 0"
if line[/.*?(\d+).*?(\d+).*?(\d+)/]
rows, cols, cells = $1.to_i, $2.to_i, $3.to_i
end
=> [10, 1, 0]
rows
=> 10
cols
=> 1
cells
=> 0