Regexp question

I have a HTML document containing many table cells of which I wish to
extract the contents.

r = Regexp.new("\<TD.*?\>(.*?)\<\TD\>", Regexp::MULTILINE)
m = r.match(table)

The above only matches the first cell, I'd like to continue the match
finding each subsequent cell. The not-very-nice way to do this is to
take the char offset of the match, create a new string from that point
and feed it back into match.

Whats the better way?

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Have you tried scan? Try the same regexp with String#scan, to get an array
of matched groups

- Shajith.

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On 5/9/05, Lyndon Samson <lyndon.samson@gmail.com> wrote:

The above only matches the first cell, I'd like to continue the match
finding each subsequent cell.

Lyndon Samson wrote:

I have a HTML document containing many table cells of which I wish to
extract the contents.

r = Regexp.new("\<TD.*?\>(.*?)\<\TD\>", Regexp::MULTILINE)
m = r.match(table)

The above only matches the first cell, I'd like to continue the match
finding each subsequent cell. The not-very-nice way to do this is to
take the char offset of the match, create a new string from that point
and feed it back into match.

Whats the better way?

Use String#scan.

    robert

Lyndon Samson, May 9:

r = Regexp.new("\<TD.*?\>(.*?)\<\TD\>", Regexp::MULTILINE)
m = r.match(table)

The above only matches the first cell, I'd like to continue the match
finding each subsequent cell. The not-very-nice way to do this is to
take the char offset of the match, create a new string from that point
and feed it back into match.

Whats the better way?

Using String#scan, as previously suggested, is the easiest method.
Another way of doing it is to use a loop while m is non-nil and match
against m.post_match on each iteration. See the documentation of the
MatchData class for more information,
        nikolai

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main(){printf(&linux["\021%six\012\0"],(linux)["have"]+"fun"-97);}