After playing a little bit with Ruby 3 years ago, I am trying to learn
it now.
Problem:
a = [“aaa”,“abb”,“bbb”,“acc”,“bcc”,“ccc”]
I want a regular expression which would extract something like [“acc”,
“ccc”] from a
I want something like
irb(main):023:0> for b in a
irb(main):024:1> b.scan("#{(a||c)}cc") && print b
irb(main):025:1> end
but I am not sure how to approach it.
Regars.
Johann
···
–
Johann Spies Telefoon: 021-808 4036
Informasietegnologie, Universiteit van Stellenbosch
"But my God shall supply all your need according to his
riches in glory by Christ Jesus." Philippians 4:19
Hello –
After playing a little bit with Ruby 3 years ago, I am trying to learn
it now.
Problem:
a = [“aaa”,“abb”,“bbb”,“acc”,“bcc”,“ccc”]
I want a regular expression which would extract something like [“acc”,
“ccc”] from a
I want something like
irb(main):023:0> for b in a
irb(main):024:1> b.scan(“#{(a||c)}cc”) && print b
irb(main):025:1> end
but I am not sure how to approach it.
I would use #select, which filters based on a condition contained
in a code block:
a = [“aaa”,“abb”,“bbb”,“acc”,“bcc”,“ccc”]
puts a.select {|e| /(a|c)cc/.match(e)}
=>
acc
ccc
David
···
On Sat, 21 Sep 2002, Johann Spies wrote:
–
David Alan Black | Register for RubyConf 2002!
home: dblack@candle.superlink.net | November 1-3
work: blackdav@shu.edu | Seattle, WA, USA
Web: http://pirate.shu.edu/~blackdav | http://www.rubyconf.com
I think I’d use Enumerable#grep in this case:
irb(main):001:0> a = [“aaa”,“abb”,“bbb”,“acc”,“bcc”,“ccc”]
[“aaa”, “abb”, “bbb”, “acc”, “bcc”, “ccc”]
irb(main):002:0> a.grep /(a|c)cc/
[“acc”, “ccc”]
~ Bruce
···
On Friday 20 September 2002 11:55 am, dblack@candle.superlink.net wrote:
I would use #select, which filters based on a condition contained
in a code block:
a = [“aaa”,“abb”,“bbb”,“acc”,“bcc”,“ccc”]
puts a.select {|e| /(a|c)cc/.match(e)}
=>
acc
ccc
David
–
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Bruce Williams http://www.codedbliss.com
iusris/#ruby-lang bruce@codedbliss.com
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