Given that:
%r{(\w,)+}.match('a,b,c')[0] #=> "a,b,"
and
%r{(\w,)+}.match('a,b,c')[1] #=> "b,"
How do I access the capture that contains "a,"?
···
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Posted via http://www.ruby-forum.com/.
Try:
%r{(\w,)+}.match('a,b,c').to_s[0..1] #=> "a,"
···
2008/4/2, Oliver Saunders <oliver.saunders@gmail.com>:
Given that:
%r{(\w,)+}.match('a,b,c')[0] #=> "a,b,"
and
%r{(\w,)+}.match('a,b,c')[1] #=> "b,"
How do I access the capture that contains "a,"?
--
Posted via http://www.ruby-forum.com/\.
--
My own blog (in polish) :
wujciol.yoyo.pl
Use scan
"a,b,c".scan(/\w+,/) --> ['a,', 'b,']
and in order to have the whole match you have to join the result of scan again.
HTH
Robert
···
On Wed, Apr 2, 2008 at 3:20 PM, Oliver Saunders <oliver.saunders@gmail.com> wrote:
Given that:
%r{(\w,)+}.match('a,b,c')[0] #=> "a,b,"
and
%r{(\w,)+}.match('a,b,c')[1] #=> "b,"
How do I access the capture that contains "a,"?
--
Posted via http://www.ruby-forum.com/\.
--
http://ruby-smalltalk.blogspot.com/
---
Whereof one cannot speak, thereof one must be silent.
Ludwig Wittgenstein
Maybe leave the plus symbol (+) out?
r = /(\w,)/
r.match('hi,a,b,c')[1]
=> "i,"
I'd probably use #scan, or even #split, instead.
Todd
···
On Wed, Apr 2, 2008 at 8:20 AM, Oliver Saunders <oliver.saunders@gmail.com> wrote:
Given that:
%r{(\w,)+}.match('a,b,c')[0] #=> "a,b,"
and
%r{(\w,)+}.match('a,b,c')[1] #=> "b,"
How do I access the capture that contains "a,"?
The reason why it's acting like this is because Regexes try to find the
largest possible match from your expression. Hence, your expression
%r{(\w,)+}.match('a,b,c')[0]
will return the first match (and largest) "a,b,"
Im sure you're asking this for a bigger reason, so you have to refine your
regular expression for that specific purpose. if you just want to split
based on a "," then simply do 'a,b,c'.split(',') which returns an array
["a", "b", "c"]
If any other, please post the actual problem.
HTH
Mutahhir.
···
On Wed, Apr 2, 2008 at 10:04 PM, Mateusz Tybura <wujciol@gmail.com> wrote:
Try:
%r{(\w,)+}.match('a,b,c').to_s[0..1] #=> "a,"
2008/4/2, Oliver Saunders <oliver.saunders@gmail.com>:
>
> Given that:
>
> %r{(\w,)+}.match('a,b,c')[0] #=> "a,b,"
>
> and
>
> %r{(\w,)+}.match('a,b,c')[1] #=> "b,"
>
> How do I access the capture that contains "a,"?
>
> --
> Posted via http://www.ruby-forum.com/\.
>
>--
My own blog (in polish) :
wujciol.yoyo.pl
Yeah, I was thinking of that regexp also, but I assumed the OP wanted
the last word letter before a comma.
Oliver, what is it that you're looking for?
Todd
···
On Wed, Apr 2, 2008 at 9:27 AM, Robert Dober <robert.dober@gmail.com> wrote:
Use scan
"a,b,c".scan(/\w+,/) --> ['a,', 'b,']
and in order to have the whole match you have to join the result of scan again.HTH
Robert
Nevermind. I was trying to parse CSV. I thought pre-written tools
weren't capable of understanding quoted values with commas inside but I
was wrong so I can use them.
I do find it amazing that you can't access multiple matches for a single
sub-pattern though. That's a serious limitation IMO.
···
--
Posted via http://www.ruby-forum.com/.
I'm not sure I understand this correctly, because I think your pattern
was wrong.
Todd
···
On Wed, Apr 2, 2008 at 10:28 AM, Oliver Saunders <oliver.saunders@gmail.com> wrote:
Nevermind. I was trying to parse CSV. I thought pre-written tools
weren't capable of understanding quoted values with commas inside but I
was wrong so I can use them.I do find it amazing that you can't access multiple matches for a single
sub-pattern though. That's a serious limitation IMO.