I did and with type -> class replacement, i get no more errors. But i also get
no output.
I'm not sure about, what should be produced. How can I get te result of the
stylesheet-application?
thanks
ralf
···
Am Donnerstag, 15. Juli 2004 14:55 schrieb Michael Neumann:
Am Donnerstag, 15. Juli 2004 14:55 schrieb Michael Neumann:
try this:
ruby xslt.rb test_style.xsl test.xml
I did and with type -> class replacement, i get no more errors. But i also get no output. I'm not sure about, what should be produced. How can I get te result of the stylesheet-application
I want to apply 'lcwa2sql.xsl' on 'lcwa-short.dia'. Using xsltproc from
libxslt, i get 'lcwa.sql'. But 'ruby xslt.rb lcwa2sql.xsl lcwa-short.dia'
produces no output.
I actually need a way to apply the stylesheets without upgrading our
production system to libxml and libxslt. And because of my growing addiction
to ruby, i came accross xslt4r.
Am Donnerstag, 15. Juli 2004 18:05 schrieb Michael Neumann:
can you give a short example?
xslt4r is in an alpha-stage. the last update was at the end of 2001!
I want to apply 'lcwa2sql.xsl' on 'lcwa-short.dia'. Using xsltproc from libxslt, i get 'lcwa.sql'. But 'ruby xslt.rb lcwa2sql.xsl lcwa-short.dia' produces no output.
I actually need a way to apply the stylesheets without upgrading our production system to libxml and libxslt. And because of my growing addiction to ruby, i came accross xslt4r.
sorry, but I no more develop xslt4r. it was just a proof of concept hack (at a boring weekend).