Passing a block around

ruby-talk
1

I want to pass a block to method foo then call method bar from foo and
have bar yield to the block, I also want to be able to call bar
directly with a block, how to do this neatly.

e.g. I want to be able to do

foo { |baz| do stuff with baz }
bar { |baz| do other stuff with baz }

but when foo gets a block it passes it to bar in the background.

Thanks,
James

2

Well, while I don't quite understand everything you've said here, the
mechanism for passing blocks around is simple:

def foo(&block)
   baz block
end

def baz(&block)
  block.call(params)
end

Hope that helps.

Jason

···

On 12/31/06, J2M <james2mccarthy@gmail.com> wrote:

I want to pass a block to method foo then call method bar from foo and
have bar yield to the block, I also want to be able to call bar
directly with a block, how to do this neatly.

e.g. I want to be able to do

foo { |baz| do stuff with baz }
bar { |baz| do other stuff with baz }

but when foo gets a block it passes it to bar in the background.

Thanks,
James

3

Hi --

···

On Mon, 1 Jan 2007, Jason Roelofs wrote:

On 12/31/06, J2M <james2mccarthy@gmail.com> wrote:

I want to pass a block to method foo then call method bar from foo and
have bar yield to the block, I also want to be able to call bar
directly with a block, how to do this neatly.

e.g. I want to be able to do

foo { |baz| do stuff with baz }
bar { |baz| do other stuff with baz }

but when foo gets a block it passes it to bar in the background.

Well, while I don't quite understand everything you've said here, the
mechanism for passing blocks around is simple:

def foo(&block)
baz block

You need &block rather than just block.

David

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