Thanks Patrick.
If I want to convert in the other direction - i.e get the ASCII value
for the characters (1..9)...
1.upto(9) { |x| puts ?x }
Does not work - it give me the ASCII code for x (which is 120) nine
times
How can I force ruby to treat the "x" as a variable and not as "x". ($x
from perlland)
Thanks
SM
···
-----Original Message-----
From: Patrick Hurley [mailto:phurley@gmail.com]
Sent: 13 April 2005 19:00
To: ruby-talk ML
Subject: Re: newbie question re: variable assignment
On 4/13/05, Simon.Mullis@equinoxsolutions.com <Simon.Mullis@equinoxsolutions.com> wrote:
Shall we find out?
We want to be the friendly news group, so starting out questions are
welcome 
Why doesn't this work?
1.upto(9) do |x|
puts ?#{x}
end
The #{ } escape is for with quoted strings. You could do something
similar to what you write using and eval; however, I think you would be
better off with:
65.upto(75) { |x| puts x.chr }
Patrick
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