Can anyone explain to me what's going on here?
···
-------------------------------------
#!/usr/bin/env ruby -w
class Thingy
attr_accessor :name
def test
puts "self.name: #{self.name}"
puts "name: #{name}"
name ||= 'default value'
puts "self.name: #{self.name}"
puts "name: #{name}"
end
end
thing1 = Thingy.new
thing1.name = 'custom value'
thing1.test
-------------------------------------
$ ruby dditest.rb
self.name: custom value
name: custom value
self.name: custom value
name: default value
-------------------------------------
I thought calling a method without a receiver (i.e. name, name=) within
an instance method would always call that method on the current object.
Is this not true for setters (i.e. Thingy#name=)?
Additionally, why is the first instance of name interpreted as a method
call and the last instance interpreted as (I think) a local variable?
Thanks,
Chris
--
Posted via http://www.ruby-forum.com/.
Hi --
I thought calling a method without a receiver (i.e. name, name=) within
an instance method would always call that method on the current object.
Is this not true for setters (i.e. Thingy#name=)?
It is not true for setters. The way it works is that when the parser
sees:
bareword = ...
it defines bareword as a local variable. Therefore, you always need
an explicit receiver for that kind of method, so Ruby will know it's a
method.
There are some interesting side-effects from this. For example:
if false
a = 1
end
puts a # nil
Even though "a = 1" is never executed, it's picked up by the parser,
and a gets defined. That's why "puts a" doesn't raise an "unknown
method or local variable" error.
Additionally, why is the first instance of name interpreted as a method
call and the last instance interpreted as (I think) a local variable?
If both are defined, the local variable takes precedence. You can
force method interpretation with parentheses:
name()
but of course in practice it's better not to reuse the names.
David
···
On Sat, 6 Jan 2007, Chris Gernon wrote:
--
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