Nested blocks

ruby-talk
1

I am trying to nest 2 blocks, it's wrong but but I cannot find why .. need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into 'places' another Array

      places = [ {:search => adresse}]

      geocodes.each { | geocode |
           places.collect { | place |
                place[:address] = geocode[:address]
                place[:latitude] = geocode[:latitude]
                place[:longitude] = geocode[:longitude]
          }
      }

geocodes.nitems => 3

geocodes[0]
=> #<struct Ym4r::GmPlugin::Geocoding::Placemark address="Rue Caulaincourt, 75018 18ème Arrondissement, Paris, France", country_code="FR", administrative_area="Ile-de-France", sub_administrative_area="Paris", locality="Paris", dependent_locality="18ème Arrondissement", thoroughfare="Rue Caulaincourt", postal_code="75018", longitude=2.333944, latitude=48.888226

geocodes[1]
=> #<struct Ym4r::GmPlugin::Geocoding::Placemark address="Lamarck - Caulaincourt, France", country_code="FR", administrative_area="Ile-de-France", sub_administrative_area="Paris", locality="Paris", dependent_locality="18ème Arrondissement", thoroughfare="Rue Caulaincourt", postal_code="75018", longitude=2.333944, latitude=48.888226>

geocodes[2]
=> #<struct Ym4r::GmPlugin::Geocoding::Placemark address="Square Caulaincourt, 75018 18ème Arrondissement, Paris, France", country_code="FR", administrative_area="Ile-de-France", sub_administrative_area="Paris", locality="Paris", dependent_locality="18ème Arrondissement", thoroughfare="Rue Caulaincourt", postal_code="75018", longitude=2.333944, latitude=48.888226

places.nitems => 1

places[0]
=> {:longitude=>2.333944, :latitude=>48.888226, :search=>"caulaincourt,75018, france", :address=>"Square Caulaincourt, 75018 18ème Arrondissement, Paris, France"}

2

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

···

On 3/5/07, Josselin <josselin@wanadoo.fr> wrote:

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

      places = [ {:search => adresse}]

      geocodes.each { | geocode |
           places.collect { | place |
                place[:address] = geocode[:address]
                place[:latitude] = geocode[:latitude]
                place[:longitude] = geocode[:longitude]
          }
      }

geocodes.nitems => 3

--
gnufied
-----------
There was only one Road; that it was like a great river: its springs
were at every doorstep, and every path was its tributary.
http://people.inxsasia.com/~hemant

3

No need for collect or collect! at all since he is modifying the Hash(es) inside places. And since places contains only 1 element it still does so after the iteration. Josselin, what do you expect to get?

Kind regards

  robert

···

On 05.03.2007 16:37, hemant wrote:

On 3/5/07, Josselin <josselin@wanadoo.fr> wrote:

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

      places = [ {:search => adresse}]

      geocodes.each { | geocode |
           places.collect { | place |
                place[:address] = geocode[:address]
                place[:latitude] = geocode[:latitude]
                place[:longitude] = geocode[:longitude]
          }
      }

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

4

Thanks for your comments..

well I expect to get 3 items (one for each geocodes item)
where places[i][:longitude] = geocodes[i][:longitude], .....
I know that I could do an iteration (as in C) but I tried to do it without using an indexation ...

places[i]
=> {:longitude=> geocodes[i][longitude], :latitude=>geocodes[i][longitude], :address=>geocodes[i][address]}

joss

···

On 2007-03-05 17:00:58 +0100, Robert Klemme <shortcutter@googlemail.com> said:

On 05.03.2007 16:37, hemant wrote:

On 3/5/07, Josselin <josselin@wanadoo.fr> wrote:

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

      places = [ {:search => adresse}]

      geocodes.each { | geocode |
           places.collect { | place |
                place[:address] = geocode[:address]
                place[:latitude] = geocode[:latitude]
                place[:longitude] = geocode[:longitude]
          }
      }

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the Hash(es) inside places. And since places contains only 1 element it still does so after the iteration. Josselin, what do you expect to get?

Kind regards

  robert

5

result = geocodes.map do |geocode|
   {:search => adresse, :address => geocode[:address], ...}
end

  robert

···

On 05.03.2007 17:21, Josselin wrote:

On 2007-03-05 17:00:58 +0100, Robert Klemme <shortcutter@googlemail.com> > said:

On 05.03.2007 16:37, hemant wrote:

On 3/5/07, Josselin <josselin@wanadoo.fr> wrote:

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

      places = [ {:search => adresse}]

      geocodes.each { | geocode |
           places.collect { | place |
                place[:address] = geocode[:address]
                place[:latitude] = geocode[:latitude]
                place[:longitude] = geocode[:longitude]
          }
      }

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the Hash(es) inside places. And since places contains only 1 element it still does so after the iteration. Josselin, what do you expect to get?

Kind regards

    robert

Thanks for your comments..

well I expect to get 3 items (one for each geocodes item)
where places[i][:longitude] = geocodes[i][:longitude], .....
I know that I could do an iteration (as in C) but I tried to do it without using an indexation ...

places[i]
=> {:longitude=> geocodes[i][longitude], :latitude=>geocodes[i][longitude], :address=>geocodes[i][address]}

joss

6

thanks.. so map and collect give the same result... not easy to forget iteration model ... so powerful methods w Ruby...

···

On 2007-03-05 17:31:31 +0100, Robert Klemme <shortcutter@googlemail.com> said:

On 05.03.2007 17:21, Josselin wrote:

On 2007-03-05 17:00:58 +0100, Robert Klemme <shortcutter@googlemail.com> said:

On 05.03.2007 16:37, hemant wrote:

On 3/5/07, Josselin <josselin@wanadoo.fr> wrote:

I am trying to nest 2 blocks, it's wrong but but I cannot find why ..
need some help.. I get only one resulting item

I get info in geocodes Array (3 items) , need to get some of them into
'places' another Array

      places = [ {:search => adresse}]

      geocodes.each { | geocode |
           places.collect { | place |
                place[:address] = geocode[:address]
                place[:latitude] = geocode[:latitude]
                place[:longitude] = geocode[:longitude]
          }
      }

geocodes.nitems => 3

#collect doesn't modify the existing Enumerable and normally returns
a Enumerable/Array.
In other words, your inner block doesn't modify places array at all.

No need for collect or collect! at all since he is modifying the Hash(es) inside places. And since places contains only 1 element it still does so after the iteration. Josselin, what do you expect to get?

Kind regards

    robert

Thanks for your comments..

well I expect to get 3 items (one for each geocodes item)
where places[i][:longitude] = geocodes[i][:longitude], .....
I know that I could do an iteration (as in C) but I tried to do it without using an indexation ...

places[i]
=> {:longitude=> geocodes[i][longitude], :latitude=>geocodes[i][longitude], :address=>geocodes[i][address]}

joss

result = geocodes.map do |geocode|
   {:search => adresse, :address => geocode[:address], ...}
end

  robert

7

Hi --

···

On Tue, 6 Mar 2007, Josselin wrote:

thanks.. so map and collect give the same result... not easy to forget iteration model ... so powerful methods w Ruby...

They're actually the same method -- just two names bound to exactly
the same thing.

David

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