hi all,
how to get time alone from this format
(1986, 1, 28, 17, 39, 18)
···
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Posted via http://www.ruby-forum.com/.
Shanmu Gam wrote:
hi all,
how to get time alone from this format
(1986, 1, 28, 17, 39, 18)
Use Time.mktime
Regards
Stefan
···
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Posted via http://www.ruby-forum.com/\.
Given the numbers I suppose that the format is as follows:
datetime = [1986, 1, 28, 17, 39, 18] # [Y, m, d, H, M, S]; array of integers
where Y is the year, m is the month, d the day, H the hour, M the minute and S the second (at least this is the order of arguments provided to Time.utc and similar functions). I am not sure what you mean by "get time". For a string representation of the time you could use:
Time.utc(*datetime).strftime("%H:%M:%S")
which in the given example returns
"17:39:18"
The same could also be done without using any Time functions using
"%02d:%02d:%0d" % datetime[-3..-1]
where %02d results in a zero-padded (hence the 0) two character (hence the 2) representation of the values. While in this case it is not needed, it makes sure that that (0, 8, 15, 1, 2, 3) results in "01:02:03" and not in "1:2:3".
In the case you start with
datetime = Time.utc(1986, 1, 28, 17, 39, 18)
and want a numerical array of hour, minute and second you can use
[datetime.hour, datetime.min, datetime.sec]
I hope I understood your question correctly.
Josef 'Jupp' Schugt
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On Wed, 10 Dec 2008 10:54:29 +0100, Shanmu Gam <shanmugam@railsfactory.org> wrote:
how to get time alone from this format
(1986, 1, 28, 17, 39, 18)
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