Hi,
Can someone explain the role of the "?" before the "x"
s = "abcdefg"
s[0] = ?x # s == "xbcdef"
I know this will accomplish the same thing.
s[0] = 'x'
Thanks,
Buzz
···
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Posted via http://www.ruby-forum.com/.
sigma ~ % irb
s = "abcdefg"
# "abcdefg"
s[0] = ?x
# 120
?x
# 120
s
# "xbcdefg"
s[0] = 'x'
# "x"
s
# "xbcdefg"
'x'[0]
# 120
s[0]
# 120
s[0,1]
# 'x'
'x'[0,1]
# 'x'
^ manveru
···
On Sun, Nov 23, 2008 at 12:35 AM, Buzz Hill <buzzhill@verizon.net> wrote:
Hi,
Can someone explain the role of the "?" before the "x"
s = "abcdefg"
s[0] = ?x # s == "xbcdef"I know this will accomplish the same thing.
s[0] = 'x'
irb(main):004:0> ?a
=> 97
It's an integer value keyword.
Programming Ruby: The Pragmatic Programmer's Guide has more
information under "Integer and Floating Point Numbers"
irb(main):005:0> x = " "
=> " "
irb(main):006:0> x[0] = ?a
=> 97
irb(main):007:0> x
=> "a"
End result for the string you modify is the same because String#=
with a single integer index accepts either integers or strings.
irb(main):002:0> x[0] = 'abc'
=> "abc"
irb(main):003:0> x
=> "abc"
-Michael Libby
···
On Sat, Nov 22, 2008 at 9:35 AM, Buzz Hill <buzzhill@verizon.net> wrote:
Hi,
Can someone explain the role of the "?" before the "x"
s = "abcdefg"
s[0] = ?x # s == "xbcdef"I know this will accomplish the same thing.
s[0] = 'x'
Michael Fellinger
Michael Libby
It's an integer value keyword.
End result for the string you modify is the same because String#=
with a single integer index accepts either integers or strings.
Thanks. I am new and not familiar with all the symbol meanings.
···
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