Lose the first character

ruby-talk
1

r = r.reverse.chop.reverse # remove the first character

That works, but I bet there's a nicer method. What do people use? I
thought there would be a pohc method (chop, in reverse).

Thanks.

(pickaxe is up in the other window, I see other ways, but I am curious
if people use one clear word, like chop!)

2

Check String. and Range

'hhelo'[ 1 .. -1 ] # for example...

···

Am 15.06.2007 um 02:35 schrieb Colin Summers:

       r = r.reverse.chop.reverse # remove the first character

That works, but I bet there's a nicer method. What do people use? I
thought there would be a pohc method (chop, in reverse).

Thanks.

(pickaxe is up in the other window, I see other ways, but I am curious
if people use one clear word, like chop!)

3

Colin Summers wrote:

       r = r.reverse.chop.reverse # remove the first character

That works, but I bet there's a nicer method. What do people use? I
thought there would be a pohc method (chop, in reverse).

if you want to lose the first *character* try r[/./m]=""
if you want to lose the first *byte* try r[0,1]=""

Daniel

4

Actually, I've been wanting a front version #chomp for a long time
too. If I has good names I'd add them to facets.

T.

···

On Jun 14, 8:35 pm, "Colin Summers" <blade...@gmail.com> wrote:

        r = r.reverse.chop.reverse # remove the first character

That works, but I bet there's a nicer method. What do people use? I
thought there would be a pohc method (chop, in reverse).

5

Daniel DeLorme wrote:

Colin Summers wrote:

       r = r.reverse.chop.reverse # remove the first character

That works, but I bet there's a nicer method. What do people use? I
thought there would be a pohc method (chop, in reverse).

if you want to lose the first *character* try r[/./m]=""

Or, non-destructively,

r = r[/.(.*)/m,1]

···

--
       vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407

6

Trans wrote, On 6/15/2007 9:47 AM:

···

On Jun 14, 8:35 pm, "Colin Summers" <blade...@gmail.com> wrote:
  

        r = r.reverse.chop.reverse # remove the first character

That works, but I bet there's a nicer method. What do people use? I
thought there would be a pohc method (chop, in reverse).
    
Actually, I've been wanting a front version #chomp for a long time
too. If I has good names I'd add them to facets.

T.

I thought the pohc! was clever. But maybe left_chop and right_chop (or lchop rchop) would be better suited names (or rchop for reverse chop)?

7

There are a million ways to do this in Ruby.
Here's a way that could be readable...
r = 'some string'
range_end = r.length - 1
r.slice!(1..range_end)

We could def a method that takes a string and does all of this. One version could return a new string, the other could trim it in place.

def nibble(string)
     range_end = string.length - 1
     string.slice(1..range_end)
end

Now we can do
r = nibble(r)

You could also just extend String.

···

On Jun 14, 2007, at 9:48 PM, Joel VanderWerf wrote:

Daniel DeLorme wrote:

Colin Summers wrote:

       r = r.reverse.chop.reverse # remove the first character

8

Hi,

>Daniel DeLorme wrote:
>>Colin Summers wrote:
>>> r = r.reverse.chop.reverse # remove the first character
>>>

We could def a method that takes a string and does all of this. One
version could return a new string, the other could trim it in place.

def nibble(string)
    range_end = string.length - 1
    string.slice(1..range_end)
end

Obey at least some conventions.

  class String
    def shift
      slice! 0, 1 if any?
    end
    alias lchop shift
  end

Bertram

···

Am Freitag, 15. Jun 2007, 23:24:29 +0900 schrieb John Joyce:

On Jun 14, 2007, at 9:48 PM, Joel VanderWerf wrote:

--
Bertram Scharpf
Stuttgart, Deutschland/Germany
http://www.bertram-scharpf.de

9

So sweet about it. What conventions do you refer to?
I said you could add to a class, I didn't do it.
I also was just trying to keep it clear.
String#slice is not well documented in rdoc. ri only gives the formats and result types.

----------------------------------------------------------- String#slice
      str[fixnum] => fixnum or nil
      str[fixnum, fixnum] => new_str or nil
      str[range] => new_str or nil
      str[regexp] => new_str or nil
      str[regexp, fixnum] => new_str or nil
      str[other_str] => new_str or nil
      str.slice(fixnum) => fixnum or nil
      str.slice(fixnum, fixnum) => new_str or nil
      str.slice(range) => new_str or nil
      str.slice(regexp) => new_str or nil

Not the most clear stuff in the world for everyone.
especially this:
      str.slice(fixnum, fixnum) => new_str or nil

Uh, what should those fixnums be?
Sure we could sit around and try it in irb, but better descriptions would be better for rdoc and for everyone.

shift is a pretty poor naming btw. Makes more sense if you are dealing with an array. Ruby's strings are not an arrays.
You missed the OP's goal. You returned the first character.

how about:

# Takes a fixnum argument. Returns a new string by removing (or nibbling) the 'fixnum' number of bytes from the string
class String
   def nibble(fixnum)
     range_end = self.length - 1
     slice(fixnum..range_end)
   end
end

···

On Jun 15, 2007, at 9:38 AM, Bertram Scharpf wrote:

Hi,

Am Freitag, 15. Jun 2007, 23:24:29 +0900 schrieb John Joyce:

On Jun 14, 2007, at 9:48 PM, Joel VanderWerf wrote:

Daniel DeLorme wrote:

Colin Summers wrote:

      r = r.reverse.chop.reverse # remove the first character

We could def a method that takes a string and does all of this. One
version could return a new string, the other could trim it in place.

def nibble(string)
    range_end = string.length - 1
    string.slice(1..range_end)
end

Obey at least some conventions.

  class String
    def shift
      slice! 0, 1 if any?
    end
    alias lchop shift
  end

Bertram