Which pattern represents any characters including space, \t \n?
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It's \s
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On Mon, Sep 1, 2008 at 10:20 AM, Zhao Yi <youhaodeyi@gmail.com> wrote:
Which pattern represents any characters including space, \t \n?
Zhao Yi wrote:
Which pattern represents any characters including space, \t \n?
The pattern that matches any character is
/./m
The /m switches the Regexp into multiline mode, and then . matches also
\n.
TPR.
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Thomas Wieczorek wrote:
> Which pattern represents any characters including space, \t \n?
It's \s
I think he actually wants /./m as he said "any character" and not "any
whitespace character".
HTH,
Sebastian
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Sebastian Hungerecker wrote:
Thomas Wieczorek wrote:
> Which pattern represents any characters including space, \t \n?
It's \s
I think he actually wants /./m as he said "any character" and not "any
whitespace character".HTH,
Sebastian
I think this is better [.\s]
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Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
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Sebastian Hungerecker wrote:
Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
Why? It should match any character.
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Zhao Yi wrote:
Sebastian Hungerecker wrote:
Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
Why? It should match any character.
From the docs, http://www.ruby-doc.org/docs/UsersGuide/rg/regexp.html
\s| space character; same as |[ \t\n\r\f]
That is not any character it is only whitespace.
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Zhao Yi wrote:
Why? It should match any character.
Yes, but so does just . when you specify the m modifier. So why make it [.\s]
if you can just do . ?
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Generally, "." matches characters including what "\s" matches.
Save your presence, I think you'd better learn more basic regular
expression knowledge first.
Zhao Yi wrote:
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Sebastian Hungerecker wrote:
Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
Why? It should match any character.
Hi --
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On Mon, 1 Sep 2008, Sebastian Hungerecker wrote:
Zhao Yi wrote:
Why? It should match any character.
Yes, but so does just . when you specify the m modifier. So why make it [.\s]
if you can just do . ?
It depends whether you want to use . without including \n somewhere
else in your regex, and therefore don't want the m modifier.
David
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On Mon, 1 Sep 2008, Peter Hickman wrote:
Zhao Yi wrote:
Sebastian Hungerecker wrote:
Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
Why? It should match any character.
From the docs, http://www.ruby-doc.org/docs/UsersGuide/rg/regexp.html
>\s| space character; same as |[ \t\n\r\f]
That is not any character it is only whitespace.
Yes, but [.\s] is a character class, consisting of any character other
than \n, plus any space including \n. So it will match any character.
David
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One reason would be that you need option /m which is effective for the
whole RX. You can avoid that by doing /(?m:.)/
Cheers
robert
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2008/9/1 Sebastian Hungerecker <sepp2k@googlemail.com>:
Zhao Yi wrote:
Why? It should match any character.
Yes, but so does just . when you specify the m modifier. So why make it [.\s]
if you can just do . ?
--
use.inject do |as, often| as.you_can - without end
Hi --
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On Mon, 1 Sep 2008, Patrick He wrote:
Generally, "." matches characters including what "\s" matches.
No, by default . does not match \n. You can make it do so with the /m
modifier.
David
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Additionally, you can use pattern "(.|\n)" if you want to match all
characters including "\n" in single line mode.
Patrick He wrote:
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Generally, "." matches characters including what "\s" matches.
Save your presence, I think you'd better learn more basic regular
expression knowledge first.Zhao Yi wrote:
Sebastian Hungerecker wrote:
Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
Why? It should match any character.
David A. Black wrote:
It depends whether you want to use . without including \n somewhere
else in your regex, and therefore don't want the m modifier.
Good point.
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Yes, thank you for reminding me. 
David A. Black wrote:
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Hi --
On Mon, 1 Sep 2008, Patrick He wrote:
Generally, "." matches characters including what "\s" matches.
No, by default . does not match \n. You can make it do so with the /m
modifier.David
Hi --
Additionally, you can use pattern "(.|\n)" if you want to match all
characters including "\n" in single line mode.
Ruby regexes don't really have a single vs. multiple line mode
distinction. They always act as if they have the Perl /m modifier in
place, so that ^ and $ match beginning and end of line but never
beginning and end of string. So Ruby's default mode is like Perl's
multi-line mode. Ruby doesn't really have a single-line mode. /m just
adds \n to the . class, so it's sort of single line, but ^ and $ still
match lines and not the whole string.
David
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On Mon, 1 Sep 2008, Patrick He wrote:
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Intro to Ruby on Rails January 12-15 Fort Lauderdale, FL
Advancing with Rails January 19-22 Fort Lauderdale, FL *
* Co-taught with Patrick Ewing!
See http://www.rubypal.com for details and updates!
Hi --
Zhao Yi wrote:
Sebastian Hungerecker wrote:
Zhao Yi wrote:
I think this is better [.\s]
No, it's not.
Why? It should match any character.
From the docs, http://www.ruby-doc.org/docs/UsersGuide/rg/regexp.html
>\s| space character; same as |[ \t\n\r\f]
That is not any character it is only whitespace.
Yes, but [.\s] is a character class, consisting of any character other
than \n, plus any space including \n. So it will match any character.
No, it's not:
>> "a" =~ /[.\n]/
=> nil
The period loses its special meaning inside a character class, so that class literally matches a period or a newline character.
James Edward Gray II
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On Sep 1, 2008, at 4:27 AM, David A. Black wrote:
On Mon, 1 Sep 2008, Peter Hickman wrote: