Is there a way to iterate through an array, getting the index and the
object at the same time?
For instance, right now I know two ways of going through an array:
array.each do |element|
print element
end
for i in 0..(array.size - 1) do |i|
print array[i]
end
Is there a way to mix these two together? As in something like
array.each do |element, i|
print element.to_s + "is at index " + i.to_s
end
without maintaining a counter through the array?
(Without doing this:
index = 0
array.each do |element|
print element.to_s + "is at index " + index.to_s
index += 1
end)
Thanks!
···
--
Posted via http://www.ruby-forum.com/.
$ri each_with_index
--------------------------------------------- Enumerable#each_with_index
enum.each_with_index {|obj, i| block } -> enum
···
On May 15, 2006, at 7:48 PM, Susan Sash wrote:
Is there a way to iterate through an array, getting the index and the
object at the same time?
------------------------------------------------------------------------
Calls block with two arguments, the item and its index, for each
item in enum.
hash = Hash.new
%w(cat dog wombat).each_with_index {|item, index|
hash[item] = index
}
hash #=> {"cat"=>0, "wombat"=>2, "dog"=>1}
-- Daniel
Too bad you disclosed the solution already - I wanted to trade it in
for those turtles...
robert
···
2006/5/15, Daniel Harple <dharple@generalconsumption.org>:
On May 15, 2006, at 7:48 PM, Susan Sash wrote:
> Is there a way to iterate through an array, getting the index and the
> object at the same time?
$ri each_with_index
--------------------------------------------- Enumerable#each_with_index
enum.each_with_index {|obj, i| block } -> enum
------------------------------------------------------------------------
Calls block with two arguments, the item and its index, for each
item in enum.
hash = Hash.new
%w(cat dog wombat).each_with_index {|item, index|
hash[item] = index
}
hash #=> {"cat"=>0, "wombat"=>2, "dog"=>1}
--
Have a look: Robert K. | Flickr