Robert Klemme wrote:
{'en' => {'A' => Fixnum, 'B' => {'C' => Fixnum, 'D' => String }}
� �newh[k] = v.is_a?(Hash) ? classify_values(v) : v.class
�end
�newh
end
p classify_values({'en' => {'A' => 1, 'B' => {'C' => 3, 'D' => 'four' }}})
I would do it a tad differently:
def classify(o)
case o
when Hash
h = {}
o.each {|k,v| h[k] = classify(v)}
h
else
o.class
end
end
Advantage is that you can stuff anything in the method while your
variant requires the argument to be a Hash. The difference may seem
subtle but if you add more collection types for special treatment,
you'll will notice a difference in effort to implement it. I can
simply do
def classify(o)
case o
when Hash
h = {}
o.each {|k,v| h[k] = classify(v)}
h
when Array
o.map {|v| classify(v)}
else
o.class
end
end
while you need to do a more complicated code change.
Kind regards
robert
Thanks, this is very helpful.
I am trying to adapt this a bit, but with no luck so far.
What I'd like to do is to start with a hash and have the above code be
additive.
In other words, if I have the following code:
h0 = {}
h1 = {'en' => {'A' => 5, 'B' => { 'C' => 'xxx', 'D' => { 'E' => 4 }}}}
h2 = {'en' => {'F' => 'yyy'}}
I'd like to be able to call the classify method like this:
puts h0.classify(h1).classify(h2).inspect
And get the following result:
{'en' => {'A' => Fixnum, 'B' => { 'C' => String, 'D' => { 'E' => Fixnum
}}, 'F' => String }}
So I figured it would be something like this:
class Hash
def classify(o)
case o
when Hash
h = self
o.each {|k,v| h[k] = classify(v)}
h
when Array
o.map {|v| classify(v)}
else
o.class
end
end
end
But this is probably wrong in a few ways. Any suggestions would be
appreciated.
Thanks.
···
2010/2/24 Xavier Noria <fxn@hashref.com>:
--
Posted via http://www.ruby-forum.com/\.