I am writing a Ruby script to accept a user's input which will be used
as a password later on. The user input it taken using STDIN.getc. Since
it is a password input, when the user enters the characters on the
keyboard, the entered characters are not displayed and each character is
obscured by displaying an asterix (*).
The code snippet is shown below.
---------START---------
def TestFunc
myPassword = ""
print "Password: "
myPassword = getPassword
print "My password: #{myPassword}\n"
end
def read_char
system "stty raw -echo"
ch = STDIN.getc
ensure
system "stty -raw echo"
return ch
end
def getPassword
password = ""
input = ""
isValidLastChar = 1
invalidCharacterDetected = 0
while (password == "") || (password != "" && input != "\r")
char = read_char
input = char.chr
if input == "\r"
next
end
if char == 127 # backspace character pressed
if password != ""
password = password.chop
print "\b \b"
end
elsif input != "" && input[0] > 32 && input[0] < 127
print "*"
password = password + input
end
end
print "\n"
return password
end
----------END----------
For this code, if I entered "1234" (without the quotes), followed by the
F1 key, the PageUp key, the Right arrow key and finally pressed Enter, I
see the following output on the screen:
-----SCREEN OUTPUT-----
[root@morpheus ~]# irb
irb(main):001:0> load "TestRuby.rb"
=> true
irb(main):002:0> testStub
Password: ***********
My password: 1234[11~[5~[C
=> nil
irb(main):004:0>
···
-----------------------
Observe the printed output.
1 -> displayed as 1
2 -> displayed as 2
3 -> displayed as 3
4 -> displayed as 4
F1 -> displayed as [11~
PgUp -> displayed as [5~
Right arrow -> displayed as [C
I am finding it difficult to figure out a way to ignore/process special
keys (F1-F12, Up/Down/Left/Right, PgUp, PgDn, Home, End, etc.).
Any suggestions or help?
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