How to wrap a long string

ruby-talk
1

Hi all,

I need to wrap a long string into several small segments.
I search the forum and see a few solutions for that. I copy one script
and run it on my Vista(with very small change) and here are the output:

C:\Documents and Settings\chen73>irb
irb(main):001:0> text = 'aaaaa11111AAAAA22222BBBBB'
=> "aaaaa11111AAAAA22222BBBBB"
irb(main):002:0> 0.step(text.length, 5) {|x| puts text[x, x+5]}
aaaaa
11111AAAAA
AAAAA22222BBBBB
22222BBBBB
BBBBB

=> 0

It looks like the script really wraps the string. But it also repeats
printing out some stuff, such two times of 'AAAAA', '22222', 3 times of
'BBBBB'.
Is it possible to get the output as follows:

aaaaa
11111
AAAAA
22222
BBBBB

Thanks,

Li

···

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2

Li Chen wrote:

text[x, x+5]

You wanted either text[x..(x+5)] or better text[x,5]. Have a look at
String#.

TPR.

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3

Considering that :

a = "1112223334444"

watch the following irb session :

irb(main):010:0> a.scan(/((.)\2+)/).collect {|match| match[0]}
=> ["111", "222", "333", "4444"]

using that regex , you'll obtain an array of matches .

···

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5

great idea!
... this will also match single letters / digits

irb(main):020:0> a = "11111122233344444445556667778888888AAABCCDEEEEF"
=> "11111122233344444445556667778888888AAABCCDEEEEF"
irb(main):021:0> puts a.scan( /((.)\2+|.)/ ).collect { |x| x[0] }
111111
222
333
4444444
555
666
777
8888888
AAA
B
CC
D
EEEE
F

regards
Karl-Heinz

···

On 25.09.2008, at 16:43, Lex Williams wrote:

Considering that :

a = "1112223334444"

watch the following irb session :

irb(main):010:0> a.scan(/((.)\2+)/).collect {|match| match[0]}
=> ["111", "222", "333", "4444"]

6

You'll miss the unrepeated characters:

> ruby -e 'p "abbcccdddd".scan(/((.)\2+)/).transpose.shift'
["bb", "ccc", "dddd"]

Where did "a" go?

Change the "+" into "*" and it'll work:

> ruby -e 'p "abbcccdddd".scan(/((.)\2*)/).transpose.shift'
["a", "bb", "ccc", "dddd"]

gegroet,
Erik V. - http://www.erikveen.dds.nl/