What is the easiest way in Ruby to make an array our of a date range?
Something like this:
@date1 = "2006-04-01"
@date2 = "2006-04-23"
array = [@date1..@date2]
Something like that would be an easy solution as @date1 and @date2 are
going to by dynamic, but this doesn't work as they are strings.
Or would I have to manually insert the ranges one by one myself?
array = ["2006-04-01", "2006-04-02", ... , "2006-04-23"]
Thanks for any help in advanced!
--
Posted via http://www.ruby-forum.com/.
im still a newbie but heres my take:
dates = []
for i in 1..23 do
if i < 10
format = "2006-04-0%d"
else
format = "2006-04-%d"
end
dates << sprintf(format, i)
end
--
Posted via http://www.ruby-forum.com/.
I don't know if this is the easiest (or best) way, but it seems to work:
require 'date' # from stdlib
# => true
(Date.parse('2006-04-01')..Date.parse('2006-04-23')).to_a.map { |e| e.to_s }
# => ["2006-04-01",
"2006-04-02",
"2006-04-03",
"2006-04-04",
...,
"2006-04-23"]
You can do a similar thing with Time to get different ranges (hours,
half-days, etc.) but it's pretty wasteful in terms of efficiency so
stick with date if you can.
a =
# =>
(Time.parse('2006-4-23')..Time.parse('2006-4-27')).step(86400) { |t| a << t }
# => Sun Apr 23 00:00:00 BST 2006..Thu Apr 27 00:00:00 BST 2006
a
# => [Sun Apr 23 00:00:00 BST 2006,
# Mon Apr 24 00:00:00 BST 2006,
# Tue Apr 25 00:00:00 BST 2006,
# Wed Apr 26 00:00:00 BST 2006,
# Thu Apr 27 00:00:00 BST 2006]
a =
# =>
(Time.parse('2006-4-23')..Time.parse('2006-4-27')).step(3600) { |t| a << t }
# => Sun Apr 23 00:00:00 BST 2006..Thu Apr 27 00:00:00 BST 2006
a
# => [Sun Apr 23 00:00:00 BST 2006,
# Sun Apr 23 01:00:00 BST 2006,
# Sun Apr 23 02:00:00 BST 2006,
# Sun Apr 23 03:00:00 BST 2006,
# Sun Apr 23 04:00:00 BST 2006,
# Sun Apr 23 05:00:00 BST 2006,
# ... 97 elements ... ]
On Sun, 2006-04-23 at 20:58 +0900, Marston A. wrote:
What is the easiest way in Ruby to make an array our of a date range?
Something like this:@date1 = "2006-04-01"
@date2 = "2006-04-23"array = [@date1..@date2]
Something like that would be an easy solution as @date1 and @date2 are
going to by dynamic, but this doesn't work as they are strings.Or would I have to manually insert the ranges one by one myself?
array = ["2006-04-01", "2006-04-02", ... , "2006-04-23"]
Thanks for any help in advanced!
--
Ross Bamford - rosco@roscopeco.REMOVE.co.uk
Date can be in a range like this:
start_date = Date.strptime("2006-04-01")
end_date = Date.strptime("2006-04-23")
date_range = start_date..end_date
puts date_range.include?(Date.strptime("2006-04-10"))
date_array = date_range.to_a
puts date_array.join(', ')
Ashley
On Apr 23, 2006, at 12:58 pm, Marston A. wrote:
What is the easiest way in Ruby to make an array our of a date range?
Something like this:@date1 = "2006-04-01"
@date2 = "2006-04-23"array = [@date1..@date2]
Something like that would be an easy solution as @date1 and @date2 are
going to by dynamic, but this doesn't work as they are strings.Or would I have to manually insert the ranges one by one myself?
array = ["2006-04-01", "2006-04-02", ... , "2006-04-23"]
Thanks for any help in advanced!
are you sure that you need an array:
harp:~ > cat a.rb
require 'date'
a = Date.parse "2006-04-01"
b = Date.parse "2006-04-23"
(a .. b).each{|date| puts date}
harp:~ > ruby a.rb
2006-04-01
2006-04-02
2006-04-03
2006-04-04
2006-04-05
2006-04-06
2006-04-07
2006-04-08
2006-04-09
2006-04-10
2006-04-11
2006-04-12
2006-04-13
2006-04-14
2006-04-15
2006-04-16
2006-04-17
2006-04-18
2006-04-19
2006-04-20
2006-04-21
2006-04-22
2006-04-23
if you do simply use
list = (a .. b).inject(){|accum, date| accum << date}
regards.
-a
On Sun, 23 Apr 2006, Marston A. wrote:
What is the easiest way in Ruby to make an array our of a date range?
Something like this:@date1 = "2006-04-01"
@date2 = "2006-04-23"array = [@date1..@date2]
Something like that would be an easy solution as @date1 and @date2 are
going to by dynamic, but this doesn't work as they are strings.Or would I have to manually insert the ranges one by one myself?
array = ["2006-04-01", "2006-04-02", ... , "2006-04-23"]
Thanks for any help in advanced!
--
be kind whenever possible... it is always possible.
- h.h. the 14th dali lama
Thank everyone, thats exactly what I needed.
--
Posted via http://www.ruby-forum.com/.
Hi --
On Sun, 23 Apr 2006, malamute jute wrote:
im still a newbie but heres my take:
dates =
for i in 1..23 do
if i < 10
format = "2006-04-0%d"
else
format = "2006-04-%d"
end
dates << sprintf(format, i)
end
I think the date library ways will scale better; but for your possible
interest, here's another way to do what you've got here:
dates = (1..23).map {|i| sprintf("2006-04-%.2d",i) }
David
--
David A. Black (dblack@wobblini.net)
Ruby Power and Light, LLC (http://www.rubypowerandlight.com)
"Ruby for Rails" PDF now on sale! Ruby for Rails
Paper version coming in early May!
Ross Bamford wrote:
(Date.parse('2006-04-01')..Date.parse('2006-04-23')).to_a.map { |e| e.to_s }
Just a small suggestion:
Leave out the to_a so it's faster and uses less memory 
if you do simply use
list = (a .. b).inject(){|accum, date| accum << date}
I'm curious, is there a special reason for the use of inject here? Doesn't the following do the same?
list = (a..b).to_a
-a
Robin
ara.t.howard@noaa.gov wrote:
Doh... I really must find my proofreading glasses
Thanks,
On Sun, 2006-04-23 at 21:59 +0900, Robin Stocker wrote:
Ross Bamford wrote:
> (Date.parse('2006-04-01')..Date.parse('2006-04-23')).to_a.map { |e| e.to_s }Just a small suggestion:
Leave out the to_a so it's faster and uses less memory
--
Ross Bamford - rosco@roscopeco.REMOVE.co.uk
Yes, they are exactly the same. It's just that inject is a force of nature. It consumes your Enumerables, and leaves a trail of devastation in its wake. You can't escape it. You must accept your fate as a slave to inject.
On Apr 23, 2006, at 1:11 PM, Robin Stocker wrote:
ara.t.howard@noaa.gov wrote:
if you do simply use
list = (a .. b).inject(){|accum, date| accum << date}I'm curious, is there a special reason for the use of inject here? Doesn't the following do the same?
list = (a..b).to_a
-a
Robin
Latterly though I've found respite from my own inject addiction thanks
to a couple of quick benchmarks:
a = (0...1000)
# => 0...1000
Benchmark.bm { |x| x.report { 100.times { a.to_a } } }
user system total real
0.060000 0.000000 0.060000 ( 0.075679)
# => true
Benchmark.bm { |x| x.report { 100.times { a.inject() { |a,e| a << e } } } }
user system total real
0.300000 0.000000 0.300000 ( 0.431041)
# => true
On Tue, 2006-04-25 at 01:42 +0900, Logan Capaldo wrote:
On Apr 23, 2006, at 1:11 PM, Robin Stocker wrote:
> ara.t.howard@noaa.gov wrote:
>> if you do simply use
>> list = (a .. b).inject(){|accum, date| accum << date}
>
> I'm curious, is there a special reason for the use of inject here?
> Doesn't the following do the same?
>
> list = (a..b).to_a
>
>> -a
>
> Robin
>Yes, they are exactly the same. It's just that inject is a force of
nature. It consumes your Enumerables, and leaves a trail of
devastation in its wake. You can't escape it. You must accept your
fate as a slave to inject.
--
Ross Bamford - rosco@roscopeco.REMOVE.co.uk
well, in this case it was merely the result of posting sans coffee. i do that
occasionally and always regret it. 
-a
On Tue, 25 Apr 2006, Logan Capaldo wrote:
On Apr 23, 2006, at 1:11 PM, Robin Stocker wrote:
ara.t.howard@noaa.gov wrote:
if you do simply use
list = (a .. b).inject(){|accum, date| accum << date}I'm curious, is there a special reason for the use of inject here? Doesn't the following do the same?
list = (a..b).to_a
-a
Robin
Yes, they are exactly the same. It's just that inject is a force of nature. It consumes your Enumerables, and leaves a trail of devastation in its wake. You can't escape it. You must accept your fate as a slave to inject.
--
be kind whenever possible... it is always possible.
- h.h. the 14th dali lama