How to make a[2][2][3]=4 work?

a=Hash.new{|h,k|
  h[k]={}
}

p a[1]=1

a[2][1]=2
#a[2][2][3]=4
p a

···

--
Posted via http://www.ruby-forum.com/.

I know this can work,but I think it is suck
a=Hash.new{|h,k|
  h[k]=Hash.new{|h,k|h[k]=Hash.new{|h,k|h[k]={}}}
}

p a[1]=1

a[2][1]=2
a[2][2][3]=4
a[3][1][1][1]=1
p a

···

--
Posted via http://www.ruby-forum.com/.

gz zz wrote:

a=Hash.new{|h,k|
  h[k]={}
}

p a[1]=1

a[2][1]=2
#a[2][2][3]=4
p a

Sure. Use Perl.

Oops, sorry. I forgot, datastructure autovivification is wrong,
variables springing into life (or maybe not, read the rest of the method
to find out) inadvertently are good.

Jenda

···

--
Posted via http://www.ruby-forum.com/\.

a = {}
    ==>{}
a[1] = 1
    ==>1
a[ [2,1] ] = 2
    ==>2
a[ [2,2,3] ] = 4
    ==>4
p a
{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
    ==>nil

···

On Jun 12, 1:29 am, gz zz <gpyg...@126.com> wrote:

a=Hash.new{|h,k|
  h[k]={}

}

p a[1]=1

a[2][1]=2
#a[2][2][3]=4

I know this can work,but I think it is suck
a=Hash.new{|h,k|
  h[k]=Hash.new{|h,k|h[k]=Hash.new{|h,k|h[k]={}}}
}

p a[1]=1

a[2][1]=2
a[2][2][3]=4
a[3][1][1][1]=1
p a

build_hash = proc {|h,k|h[k] = Hash.new &build_hash }
a = Hash.new &build_hash

def recursive_hash
  Hash.new { |h, k| h[k] = recursive_hash }
end
a = recursive_hash

Or even

class Hash
  def self.recursive
    new { |h, k| h[k] = recursive }
  end
end

which gives

a = Hash.recursive

=>

a[1][2][3][4] = 1

=> 1

puts a.inspect

{1=>{2=>{3=>{4=>1}}}}

···

--
Sylvain Joyeux

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

gz zz <gpygood@126.com> writes:

a[2][1]=2
a[2][2][3]=4
a[3][1][1][1]=1
p a

irb(main):001:0> a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}
=> {}
irb(main):002:0> a[2][1]=2
=> 2
irb(main):003:0> a[2][2][3]=4
=> 4
irb(main):004:0> a[3][1][1][1]=1
=> 1
irb(main):005:0> p a
{2=>{1=>2, 2=>{3=>4}}, 3=>{1=>{1=>{1=>1}}}}
=> nil

···

--
s=%q( Daniel Martin -- martin@snowplow.org
       puts "s=%q(#{s})",s.to_a.last )
       puts "s=%q(#{s})",s.to_a.last

That's okay, it happens to the best of us.

martin

···

On 6/12/07, Jenda Krynicky <jenda@cpan.org> wrote:

Sure. Use Perl.

Oops, sorry. I forgot, datastructure autovivification is wrong,
variables springing into life (or maybe not, read the rest of the method
to find out) inadvertently are good.

Sure. Use Perl.

What's the ruby-way of such things?

e.g.:

   int[eth0][ip] = "10.0.0.1"
   int[eth0][mask] = "255.255.255.0"
   int[eth0][cidr] = "24"
   int[eth1][ip] = "10.0.1.1"
   int[eth1][mask] = "255.255.255.0"
   int[eth1][cidr] = "24"
   .
   .
   .

I like it if I have all these informations handy within one hash. But
even for me as a realy ruby-newby this looks much more like perl than
ruby.

It would be great to hear your thoughts how this would be done "the ruby
way"...

clean and elegant :slight_smile:

--fsormok

···

--
Posted via http://www.ruby-forum.com/\.

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

irb(main):026:0> require 'ostruct'
irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

a = {}
   ==>{}
a[1] = 1
   ==>1
a[ [2,1] ] = 2
   ==>2
a[ [2,2,3] ] = 4
   ==>4
p a
{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
   ==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and
clean but when it comes to hashes of hashes it gets kind of complicated.
For me it looks like ruby has another "concept" of solving such things.

-fsormok

···

--
Posted via http://www.ruby-forum.com/\.

Thanks for this - I didn't know about the default_proc method. Quite
elegant in this case.

···

On Jun 12, 6:21 am, Daniel Martin <mar...@snowplow.org> wrote:

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

Sure. Use Perl.

What's the ruby-way of such things?

e.g.:

  int[eth0][ip] = "10.0.0.1"
  int[eth0][mask] = "255.255.255.0"
  int[eth0][cidr] = "24"
  int[eth1][ip] = "10.0.1.1"
  int[eth1][mask] = "255.255.255.0"
  int[eth1][cidr] = "24"
  .

I like it if I have all these informations handy within one hash. But
even for me as a realy ruby-newby this looks much more like perl than
ruby.

It would be great to hear your thoughts how this would be done "the ruby
way"...

clean and elegant :slight_smile:

You can do that in Ruby, if you want to.
See: http://blade.nagaokaut.ac.jp/cgi-bin/scat.rb/ruby/ruby-talk/255313

irb(main):011:0> int = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}
=> {}
irb(main):012:0> int[:eth0][:ip] = "10.0.0.1"
irb(main):013:0> int[:eth0][:mask] = "255.255.255.0"
irb(main):014:0> int[:eth0][:cidr] = "24"
irb(main):015:0> int[:eth1][:ip] = "10.0.1.1"
irb(main):016:0> int[:eth1][:mask] = "255.255.255.0"
irb(main):017:0> int[:eth1][:cidr] = "24"
irb(main):018:0> int
=> {:eth0=>{:ip=>"10.0.0.1", :mask=>"255.255.255.0", :cidr=>"24"}, :eth1=>{:ip=>"10.0.1.1", :mask=>"255.255.255.0", :cidr=>"24"}}

Another possibility might be OpenStruct.

irb(main):026:0> require 'ostruct'
=> true
irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}
=> {}
irb(main):028:0> int[:eth0].ip = "10.0.0.1"
irb(main):029:0> int[:eth0].mask = "255.255.255.0"
irb(main):030:0> int[:eth0].cidr = "24"
irb(main):031:0> int[:eth1].ip = "10.0.1.1"
irb(main):032:0> int[:eth1].mask = "255.255.255.0"
irb(main):033:0> int[:eth1].cidr = "24"
irb(main):034:0> int
=> {:eth0=>#<OpenStruct ip="10.0.0.1", mask="255.255.255.0", cidr="24">, :eth1=>#<OpenStruct ip="10.0.1.1", mask="255.255.255.0", cidr="24">}

Regards,

Bill

···

From: "Fsormok Fsormok" <fsormok@inbox.ru>

Hmm the context of this statement seems not complete in *this* thread,
maybe you could elaborate on this a little bit?
Personally I feel that Ruby's concept of Hashes is clearcut and
exactly the same as in most of its relatives (Perl,Python...).

What exactly would you like to have "simpler"?

Cheers
Robert

···

On 7/23/07, Fsormok Fsormok <fsormok@inbox.ru> wrote:

> a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

> irb(main):026:0> require 'ostruct'
> irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

>a = {}
> ==>{}
>a[1] = 1
> ==>1
>a[ [2,1] ] = 2
> ==>2
>a[ [2,2,3] ] = 4
> ==>4
>p a
>{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
> ==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and
clean but when it comes to hashes of hashes it gets kind of complicated.
For me it looks like ruby has another "concept" of solving such things.

--
As simple as possible,
but not simpler.
-- A. Einstein

In my personal opinion, multilevel hashes aren't clean and elegant in
any language. I'd try to make an object out of it:

class Interface
  attr_accessor :name, :ip, :mask, :cidr
end

i = Interface.new
i.name = "eth0"
i.ip = "10.0.0.1"
i.mask = "255.255.255.0"
i.cidr = 24

- Mark.

···

On Jul 20, 1:57 pm, Fsormok Fsormok <fsor...@inbox.ru> wrote:

> Sure. Use Perl.

What's the ruby-way of such things?

e.g.:

   int[eth0][ip] = "10.0.0.1"
   int[eth0][mask] = "255.255.255.0"
   int[eth0][cidr] = "24"
   int[eth1][ip] = "10.0.1.1"
   int[eth1][mask] = "255.255.255.0"
   int[eth1][cidr] = "24"
   .
   .
   .

I like it if I have all these informations handy within one hash. But
even for me as a realy ruby-newby this looks much more like perl than
ruby.

It would be great to hear your thoughts how this would be done "the ruby
way"...

clean and elegant :slight_smile:

> a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

> irb(main):026:0> require 'ostruct'
> irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

>a = {}
> ==>{}
>a[1] = 1
> ==>1
>a[ [2,1] ] = 2
> ==>2
>a[ [2,2,3] ] = 4
> ==>4
>p a
>{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
> ==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and
clean but when it comes to hashes of hashes it gets kind of complicated.
For me it looks like ruby has another "concept" of solving such things.

Its this what you are looking for?

$ ruby <<XXX

miss = lambda {|h,k| h[k] = Hash.new(&miss)}
hash = Hash.new(&miss)
hash[1][2]=3
hash[4]=5
p hash
XXX

{1=>{2=>3}, 4=>5}

Kind regards

robert

···

2007/7/23, Fsormok Fsormok <fsormok@inbox.ru>:

Daniel Martin wrote:

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

That's clever, but I think the way it automatically creates keys is
wrong. You need to be able to check to see if a key exists without
polluting the hash with a bunch of empties.

Hence my new gem:

http://github.com/dasil003/safe-nested-hash

···

--
Posted via http://www.ruby-forum.com/\.

Thanx Mark

This is exactly what i liked to hear :slight_smile:

In my personal opinion, multilevel hashes aren't clean and elegant in
any language.

HoH are quiet common in perl (at least I use them alot), not in Ruby
IMHO.

But as always: TMTOWTDI

···

I'd try to make an object out of it:

class Interface
  attr_accessor :name, :ip, :mask, :cidr
end

i = Interface.new
i.name = "eth0"
i.ip = "10.0.0.1"
i.mask = "255.255.255.0"
i.cidr = 24

- Mark.

--
Posted via http://www.ruby-forum.com/\.