I solved table of multiplication from 1 -10 program like follows:
x = 1
while x <= 10
puts " #{x} * 1 = #{x}" " " " #{x} * 2 = #{x*2}" " " " #{x} * 3 =
#{x*3}"......" #{x} * 1 = #{x*10}"
x = x + 1
end
From above program I am getting output improper way.
My question is how can I get output in proper way.
Thank you.
--
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Jaimin Pandya wrote in post #1137467:
From above program I am getting output improper way.
My question is how can I get output in proper way.
Add some commas.
For future reference, it also helps if you define "improper" and
"proper". For all we know you might want it all concatenated on a single
line.
--
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hi Jaimin Pandya,
x = 1
while x <= 10
puts "#{x} * 1 = #{x} , #{x} * 2 = #{x*2}, #{x} * 3 = #{x*3}......
#{x} * 1 = #{x*10}"
x = x + 1
end
Use the code above it's working.
--
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2.upto(9) { |a| 1.upto(9) {|b| print "%3d" % (a*b)} ; puts }
2 4 6 8 10 12 14 16 18
3 6 9 12 15 18 21 24 27
4 8 12 16 20 24 28 32 36
5 10 15 20 25 30 35 40 45
6 12 18 24 30 36 42 48 54
7 14 21 28 35 42 49 56 63
8 16 24 32 40 48 56 64 72
9 18 27 36 45 54 63 72 81
Is it 'proper' ?
--
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I want to do program that's output should formatted as below:
1 * 1 = 1 2 * 1 = 2 3 * 1 = 3 ----------- 10 * 1 = 10
1 * 2 = 2 2 * 2 = 4 3 * 2 = 6 ----------- 10 * 2 = 20
-------------------------------------------------------------
-------------------------------------------------------------
--------------------------------------------------------------
1 * 10 = 10 2 * 10 = 20 3 * 10 = 30 --------- 10 * 10 = 100
I am not getting output like above.
could anyone help me on this?
Thank you.
--
Posted via http://www.ruby-forum.com/.
I want to do program that's output should formatted as below:
1 * 1 = 1 2 * 1 = 2 3 * 1 = 3 ----------- 10 * 1 = 10
1 * 2 = 2 2 * 2 = 4 3 * 2 = 6 ----------- 10 * 2 = 20
-------------------------------------------------------------
-------------------------------------------------------------
--------------------------------------------------------------
1 * 10 = 10 2 * 10 = 20 3 * 10 = 30 --------- 10 * 10 = 100
I am not getting output like above.
could anyone help me on this?
Run this code, It may be as your's :
x = 1
while x<=10
(1..10).each do |n|
puts "\n" if n ==1
print "#{x}*#{n}=#{x*n}"+"\t"
end
x += 1
end
--
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Nice, compact and easy to understand.
You should probably use a '1.upto...' in the outer loop so the output
shows what is being multiplied.
From: Regis d'Aubarede <lists@ruby-forum.com>
To: ruby-talk@ruby-lang.org
Date: 02/21/2014 11:38 AM
Subject: Re: How to do table of multiplication of number program in
Ruby?
"ruby-talk" <ruby-talk-bounces@ruby-lang.org> wrote on 02/21/2014 11:38:23 AM:
Sent by: "ruby-talk" <ruby-talk-bounces@ruby-lang.org>
> 2.upto(9) { |a| 1.upto(9) {|b| print "%3d" % (a*b)} ; puts }
2 4 6 8 10 12 14 16 18
3 6 9 12 15 18 21 24 27
4 8 12 16 20 24 28 32 36
5 10 15 20 25 30 35 40 45
6 12 18 24 30 36 42 48 54
7 14 21 28 35 42 49 56 63
8 16 24 32 40 48 56 64 72
9 18 27 36 45 54 63 72 81Is it 'proper' ?
--
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Raja gopalan wrote in post #1137469:
hi Jaimin Pandya,
x = 1
while x <= 10
puts "#{x} * 1 = #{x} , #{x} * 2 = #{x*2}, #{x} * 3 = #{x*3}......
#{x} * 1 = #{x*10}"
x = x + 1
endUse the code above it's working. The problem in your code is: "......"
Thank you for your reply.
I tried this program and output came correct. But output is not come in
table form.
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Regis d'Aubarede wrote in post #1137513:
1.upto(9) { |a| 1.upto(9) {|b| print "%3d%s" % [(a*b),b==1? "|" : ""]} ;
puts "\n"+(a==1 ? '-'*30 : "")}
1| 2 3 4 5 6 7 8 9
------------------------------
2| 4 6 8 10 12 14 16 18
3| 6 9 12 15 18 21 24 27
4| 8 12 16 20 24 28 32 36
5| 10 15 20 25 30 35 40 45
6| 12 18 24 30 36 42 48 54
7| 14 21 28 35 42 49 56 63
8| 16 24 32 40 48 56 64 72
9| 18 27 36 45 54 63 72 81Is it 'proper' ?
Yes, It is proper.
Which type of output I want? That I just posted with format of output.
Thank you.
--
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Matthew Kerwin wrote in post #1137468:
Jaimin Pandya wrote in post #1137467:
From above program I am getting output improper way.
My question is how can I get output in proper way.
Add some commas.
For future reference, it also helps if you define "improper" and
"proper". For all we know you might want it all concatenated on a single
line.
Thank you.
--
Posted via http://www.ruby-forum.com/.
Jaimin Pandya wrote in post #1138537:
I want to do program that's output should formatted as below:
1 * 1 = 1 2 * 1 = 2 3 * 1 = 3 ----------- 10 * 1 = 10
1 * 2 = 2 2 * 2 = 4 3 * 2 = 6 ----------- 10 * 2 = 20
-------------------------------------------------------------
-------------------------------------------------------------
--------------------------------------------------------------1 * 10 = 10 2 * 10 = 20 3 * 10 = 30 --------- 10 * 10 = 100
I am not getting output like above.
could anyone help me on this?
Thank you.
Run this code, It may be as your's :
x = 1
while x<=10
(1..10).each do |n|
puts "\n" if n ==1
print "#{x}*#{n}=#{x*n}"+"\t"
end
x += 1
end
--
Posted via http://www.ruby-forum.com/.
Jaimin Pandya wrote in post #1138537:
I want to do program that's output should formatted as below:
1 * 1 = 1 2 * 1 = 2 3 * 1 = 3 ----------- 10 * 1 = 10
1 * 2 = 2 2 * 2 = 4 3 * 2 = 6 ----------- 10 * 2 = 20
-------------------------------------------------------------
-------------------------------------------------------------
--------------------------------------------------------------1 * 10 = 10 2 * 10 = 20 3 * 10 = 30 --------- 10 * 10 = 100
I am not getting output like above.
could anyone help me on this?
Thank you.
Run also this code to get the thing which is same to your's thing.
1..10).each do |a|
(1..10).each do |b|
print "#{a}*#{b}=#{a*b}"+"\t"
end
end
--
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Thank you.
Run this code, It may be as your's :
x = 1
while x<=10
(1..10).each do |n|
puts "\n" if n ==1
print "#{x}*#{n}=#{x*n}"+"\t"
end
x += 1
end
I got desire output from your answer.
Thank you very much.
--
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Run also this code to get the thing which is same to your's thing.
1..10).each do |a|
(1..10).each do |b|
print "#{a}*#{b}=#{a*b}"+"\t"
end
end
In above program, one code "puts "\n" if b == 1" is missing above this
code( print "#{a}*#{b}=#{a*b}"+"\t" ).
Thank you.
--
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("01".."99").each { |s| a,b=s.chars
print "%6s=%-2d" % [(c=("%s*%s"% [a,b])),eval(c)] if a!="0" && b!="0"
puts if b=="9"
}
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